Question

Stadium has 48,000 seats seats sell for $30 in section 8 $24 in section B and $18 in section C the number of seats in section a equals the total number of seats in section BNC supposed to stadium takes in 1,239,600 From each sold out that how many seats does each section whole

Answer 1

Answer:there are  24,000 sears in section A,  14,600 in section B  and  19,400 in section C.

Step-by-step explanation:

Step 1

let  the number of seats in section B = x

and the number of seats in section C.=y

Given that the  number of seats in section A is the sum of seats in sections B and C, we can then say A =x + y

From the given question,  We have that

seatsA + seatsB + seatsC = 48,000 which also equals

(x+y)  + x      + y      = 48,000

2x + 2y = $48,000

2(x+y) = 48,000

x + y = 48,000/2 =24,000  which also equals

B+C =24,000

Now the number of seats in section A =24,000 and the sum of seats in sections B and C is 24000.

We now have

B+C = 24,000------ eqn  (1)

Also

  since we already have the number of seats for Section A, We will find Section  B and C  

A +B+C =1,239,600,

$30 x 24,000 + 24B + 18C= 1,239,600

720,000 + 24B + 18C= 1,239,600

 24B + 18C= 1,239,600-720,000

24B + 18C= 519,600--------- eqn 2

Step 2 We will now solve with the following equations

B+C = 24,000------ eqn  (1)

24B + 18C= 519,600--------- eqn 2

Multiply eq(1) by 24 (both sides). Then subtract eq(2) from it:

24B + 24C = 576,000-------eqn    (3)

24B+ 18C =   519,600-- ---eqn(4)

6C = 576,000- 519,600

6C=56,400

C= 9,400

TO get B.

B+C = 24,000

B= 24,000 - 9,400

B=14,600

Therefore, there are 24,000 sears in section A,  14,600 in section B  and  19,400 in section C.