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velikii [3]
3 years ago
7

Solve system of linear equation by substitution -x+y=2; 3x-5y=-4

Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

(-3,-1)

Step-by-step explanation:

-x+y=2

3x-5y=-4

in the top equation, we can get y by itself on one side of the equation:

-x+y=2

y=x+2

now, since we know that y=x+2, in the bottom equation we can substitute x+2 for y (substitution method) and solve:

3x-5y=-4

3x-5(x+2)=-4

3x-5x-10=-4

-2x-10=-4

-2x=6

x=-3

since we now know that x=-3, we can use it to find y by plugging in -3 for x in the top equation (you can do it in either equation, but doing it in the top equation is easier):

y=x+2

y=-3+2

y=-1

answer: (-3, -1)

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2 years ago
2sin^2x - sinx - 3 = 0
e-lub [12.9K]
We have that
2sin²<span>x - sinx - 3 = 0
</span>
Let
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so
2A²-A-3=0

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see the attached figure

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A=-1
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8 0
3 years ago
Please help with the question,
castortr0y [4]
The correct answer is x^2-2x+2=0

 The explanation is shown below:

 1. To solve the problem shown in the figure above, you must apply the following proccedure:

 2. You have that the roots of the quadratic equation shown in the figure attached in the problem are:

  x=-1±i

 3.  Then, you know the quadratic formula to solve quadratic equations, which is:

 (-b±√(b^2-4ac))/2a

 4. You can see in the figure that a=1 and c=2; then, by analizing this, you can conclude that the coefficient b is:

 b=-2

 5. Therefore, you can conclude tha the quadratic equation is:

 x^2-2x+2=0

 6. If you want to verify it, apply the quadratic formula to the quadratic equation shown above and you will obtain the roots shown in the figure.
8 0
2 years ago
Read 2 more answers
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