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2 years ago

Can someone help me with this math work i really don't get it.

Mathematics

1 answer:

MariettaO [177]2 years ago

7 0

Answer:

Step-by-step explanation:

opens down refers to the value of a being negative or positive. If it opens down, then a is negative.

shifting left or right refers to the value of h

shifting up or down refers to the value of k

For the first one: y = -a (x+8)² + k

second one: y = -a(x+h)² + 7

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Determine the decibel values of thermal noise power (N) and thermal noise power density (No) given the following: T=292 degrees

Agata [3.3K]

Answer: d. None of the above are correct.

Step-by-step explanation: Noise is a superfluous random alteration in an eletrical signal. There are different types of noises created by different devices and process. Thermal noise is one of them. It is unavoidable because is created by the agitation of the charge carriers, due to temperature, inside an eletrical conductor at equilibrium and is present in all eletrical circuits.

The formula to find the thermal noise power (N) is: N = $k_{b}$ .T.B, where:

$k_{b}$ is Boltzmann constant (1.38. $10^{-23}$ J/K);

T is temperature in Kelvin;

B is the bandwith;

Calculating the thermal noise power:

N = 1.38. $10^{-23}$ ·292·40

N = 16118.4. $10^{-23}$ dBm

The thermal noise power [N] = 16118.4. $10^{-23}$ dBm

Noise power density or simply Noise density (N₀) is the noise power per unit of bandwith and its SI is watts per hertz.

For thermal noise, N₀ = kT, where

k is the Boltzmann constant in J/K;

T is the receiver system noise temperature in K;

N₀ = 1.38. $10^{-23}$ . 292

N₀ = 402.96. $10^{-23}$ W/Hz

The thermal noise power density [N₀] = 402.96. $10^{-23}$ W/Hz

7 0

3 years ago

Please help... I have no clue

muminat

Answer:

OPTION C: Sin C - Cos C = s - r

Step-by-step explanation:

ABC is a right angled triangle. ∠A = 90°, from the figure.

Therefore, BC = hypotenuse, say h

Now, we find the length of AB and AC.

We know that: $\textbf{Sin A} = \frac{\textbf{opp}}{\textbf{hyp}}$

and $\textbf{Cos A} = \frac{\textbf{adj}}{\textbf{hyp}}$

Given, Sin B = r and Cos B = s

⇒ $Sin B = r = \frac{opp}{hyp} = \frac{AC}{BC} = \frac{AC}{h}$

⇒ $\textbf{AC} = \textbf{rh}$

Hence, the length of the side AC = rh

Now, to compute the length of AB, we use Cos B.

$Cos B = s = \frac{adj}{hyp} = \frac{AB}{BC} = \frac{AB}{h}$

⇒ $\textbf{AB} = \textbf{sh}$

Hence, the length of the side AB = sh

Now, we are asked to compute Sin C - Cos C.

$Sin C = \frac{opp}{hyp}$

⇒ $Sin C = \frac{AB}{BC}$

$= \frac{sh}{h}$

= s

Sin C = s

$Cos C = \frac{adj}{hyp}$

$\implies Cos C = \frac{AC}{BC}$

⇒ Cos C = $\frac{rh}{h}$

Therefore, Cos C = r

So, Sin C - Cos C = s - r, which is OPTION C and is the right answer.

5 0

3 years ago

The weights in pounds of five cats are 12, 14, 12, 16, and 16. Find the mean, median, mode, and range of the data set.

ahrayia [7]

Jvucupjeghrjtkkffjjrhfb over cztTzvo xis divi. I thrush kB

5 0

3 years ago

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! Multiply. (2 − 5i)(3 + i)

ANEK [815]

(2-5i)(3+i)

use foil method to expand it into standard form

6+2i-15i+5i^2

5i^2-13i+6

7 0

3 years ago

Directions: Find the inverse of each number.

Alisiya [41]

Answer:

Step-by-step explanation:

Additive inverse:

-3=3

14=-14

-28=28

-1/5=1/5

Multiplicative Inverse:

2/3=3/2

6/18=18/6

5=1/5

11=1/11

3 0

1 year ago

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