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Vilka [71]
3 years ago
14

PLZ HELP ASAP 50 PTS (MATH) + Brainliest

Mathematics
2 answers:
damaskus [11]3 years ago
8 0

Answer:

  1. x+3 and x+2
  2. ( 5 x + 2 ) ( x 2 + 5 )
  3. 9x^2+16
  4. 3x2 + 21x + 36

Step-by-step explanation:

  1. x2 + 5x + 6

Let us try factorizing this polynomial using splitting the middle term method.

Factoring polynomials by splitting the middle term:

We need to find two numbers ‘a’ and ‘b’ such that a + b =5 and ab = 6.

On solving this we obtain, a = 3 and b = 2

Thus, the above expression can be written as:

x2 + 5x + 6

= x2 + 3x + 2x + 6

= x(x + 3) + 2(x + 3)

= (x + 3)(x + 2)

Thus, x+3 and x+2 are the factors of the polynomial x2 + 5x + 6.

  • For Step 1, you just want to find all combinations of two numbers that multiply together to be 56. Make sure you take negatives into account. Those pairs of numbers are:

 

(p, q, p+q)

(1, 56, 57)

(-1, -56, -57)

(2, 28, 30)

(-2, -28, -30)

(4, 14, 18)

(-4, -14, -18)

(7, 8, 15)

(-7, -8, -15)

 

Use those pairs of numbers and their sums to fill in the three columns of your table.

  • STEP 2  
  • Look down your p+q column to find the pair of numbers that add up to equal to -15. That's (p, q) = (-7, -8).  
  • STEP 3  
  • Using the information from steps 1 and 2, you can factor the trinomial like this:  
  • x2 - 15x + 56 = (x + p)(x + q) = (x - 7)(x - 8)  
  • FOIL that back out if you'd like, to make sure the expressions are equivalent.
  •  STEP 4  
  • Hopefully, seeing steps 1 through 3 worked out will help you with step 4. Find all the pairs of numbers that multiply together to be 36 (1 and 36, 2 and 18, 3 and 12, 4 and 9, 6 and 6, and all their negative equivalents), then figure out which pair has a sum of 12. That means you've found your p and q, and can factor the trinomial as (x + p)(x + q).
MrRissso [65]3 years ago
5 0

Answer:

1) Factor the trinomial. Show ALL work:

(x-2)(x-3) steps see explanation

2) Factor the polynomial using grouping.

Group and factor out the greatest common factor (GCF), then combine.

(5x-2) (x^{2} +5)

4) Choose ONE of the following polynomial and factor completely.

15x2 − 35 = 5 (3x^2-7)

Step-by-step explanation:

x2−5x+6

The middle number is -5 and the last number is 6.

Factoring means we want something like

(x+_)(x+_)

We need two numbers that

Add together to get -5

Multiply together to get 6

Try -2 and -3:

-2+-3 = -5

-2*-3 = 6

Fill in the blanks in

(x+_)(x+_)

with -2 and -3 to get...

(x-2)(x-3)

4( Choose ONE of the following polynomial and factor completely,

15x^2-35

35 as 5*7

15 as 5*3

= 5*3x^2-5*7

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Friday night.: 48/3 =16 so each ticket costs $16

Saturday night 36/2= 18 so each ticket costs $18

Brother collects 96/6 = 16. So each person had enough for a $16 ticket. They can go to the Friday night concert. They paid for the least expensive ticket.

8 0
4 years ago
Match the features of the graph of the rational function.
Sunny_sXe [5.5K]

After applying <em>algebraic</em> analysis we find the <em>right</em> choices for each case, all of which cannot be presented herein due to <em>length</em> restrictions. Please read explanation below.

<h3>How to analyze rational functions</h3>

In this problem we have a rational function, whose features can be inferred by algebraic handling:

Holes - x-values that do not belong to the domain of the <em>rational</em> function:

x³ + 8 · x² - 9 · x = 0

x · (x² + 8 · x - 9) = 0

x · (x + 9) · (x - 1) = 0

x = 0 ∨ x = - 9 ∨ x = 1

But one root is an evitable discontinuity as:

y = (9 · x² + 81 · x)/(x³ + 8 · x² - 9 · x)

y = (9 · x + 81)/(x² + 8 · x - 9)

Thus, there are only two holes. (x = - 9 ∨ x = 1) Besides, there is no hole where the y-intercept should be.

Vertical asymptotes - There is a <em>vertical</em> asymptote where a hole exists. Hence, the function has two vertical asymptotes.

Horizontal asymptotes - <em>Horizontal</em> asymptote exists and represents the <em>end</em> behavior of the function if and only if the grade of the numerator is not greater than the grade of the denominator. If possible, this assymptote is found by this limit:

y = \lim_{x \to \pm \infty} \frac {9\cdot x + 81}{x^{2}+8\cdot x - 9}

y = 0

The function has a horizontal asymptote.

x-Intercept - There is an x-intercept for all x-value such that numerator is equal to zero:

9 · x + 81 = 0

x = - 9

There is a x-intercept.

Lastly, we have the following conclusions:

  1. How many holes? 2
  2. One <em>horizontal</em> asymptote along the line where y always equals what number: 0
  3. This function has x-intercepts? True
  4. One <em>vertical</em> asymptote along the line where x always equals what number: 1
  5. There is a hole where the y-intercept should be? False

To learn more on rational functions: brainly.com/question/27914791

#SPJ1

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3 0
3 years ago
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Find the value of x<br> (6x + 7)°<br> (8x - 17)°
Vlad [161]
<h3>Answer:  x = 12</h3>

Explanation:

The two angles shown are vertical angles. This occurs whenever you have an X shape like this, and whenever the angles are opposite one another. Vertical angles are always congruent.

6x+7 = 8x-17

6x-8x = -17-7

-2x = -24

x = -24/(-2)

x = 12

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3 years ago
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