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DIA [1.3K]
2 years ago
9

Kenyon ran for 8 miles each week while training. Here is his record of the number of miles he ran.

Mathematics
1 answer:
diamong [38]2 years ago
8 0

Step-by-step explanation:

Let x be the miles Kenyon ran on tuesday

Let y be the miles Kenyon ran on thursday

Given,

Mon + Tues + Wed + Thu = 8mi

1.2 + x + 1.6 + y = 8 \\ 2.8 + x + y = 8 \\ x + y = 8 - 2.8 \\ x + y = 5.2

also given,

y = x + 0.4 \\  - x + y = 0.4

Now we have x + y = 5.2 as equation 1 and -x + y = 0.4 as equation 2

Using equation 1,

x + y = 5.2 \\ x = 5.2 - y

Substitute this equation into equation 2.

- (5.2 - y) + y = 0.4 \\  - 5.2 + y + y = 0.4 \\  - 5.2 + 2y = 0.4 \\ 2y = 0.4 + 5.2 \\ 2y = 5.6 \\ y = 5.6 \div 2 \\  = 2.8mi

Substitute y = 2.8 into equation 1.

x + 2.8 = 5.2 \\ x = 5.2 - 2.8 \\  = 2.4mi

Therefore Kenyon ran 2.4 miles on tuesday, and ran 2.8 miles on thursday.

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Perimeter of Isosceles Triangle = 2x + 8
                                                  = 2(5) + 8
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SVEN [57.7K]
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7 0
4 years ago
Help due today please ​
horsena [70]

Answer:

<em>angle ABD =</em><u><em>55 degree</em></u>

<em>angle BCD= </em><u><em>125 degree</em></u>

Step-by-step explanation:

angle ABD and angle DBC are supplementary angles.

Hence, angle ABD +angle DBC = 180 --equation 1

angle ABD = (2x+15) ---equation 2

angle BCD = (4x+45) ------equation 3

ABD+DBC=180

(2x+15) + ( 4x+45 ) = 180

2x+4x+15+45=180

6x+60=180

6x=180-60

6x=120

x=120/6=20

angle ABD= 2x+15= 2(20) +15

                              =40+15= 55 degree

angle BCD= 4x+45 = 4(20) +45

                                = 80+45= 125 degree

Hence, angle ABD =55 degree

            angle BCD= 125 degree

<em>Hope this helps.</em>

7 0
3 years ago
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