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Harrizon [31]
2 years ago
14

Ben and Arnoldo are sharing snacks. They have peanut treats and coconut treats. Ben ate 2 of the peanut treats and 4 of the coco

nut treats for a total of 160 calories. Arnoldo ate 3 of the peanut treats and 2 of the coconut treats for a total of 140 calories. They wrote the system below to represent the number of calories there are in the two types of treats.
2 x + 4 y = 160. 3 x + 2 y = 140.

They found the solution to be (30, 25). How many calories are in each treat?
There are 25 calories in each peanut treat and 30 calories in each coconut treat.
There are 30 calories in each peanut treat and 25 calories in each coconut treat.
There are 28 calories in each peanut treat and 28 calories in each coconut treat.
There are 55 calories in each peanut treat and 55 calories in each coconut treat.
Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0

the answer is 21 it really not it just I have to do this for this app that won't give me these for answers

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Determine if each function is linear or nonlinear.
Akimi4 [234]

Answer:

Linear: y = x, y = x/2 - 3, 3x + 2 = 12

Nonlinear: y = 6/x - 2, y = 3x^3 + 5

Step-by-step explanation:

Linear functions form straight lines while nonlinear functions do not.

3 0
3 years ago
(-2x-1)^2=0 How to solve brackets, please help
malfutka [58]
Not quite sure what you mean by brackets, but you can get the solution to this equation in a few steps:

<span>(-2x - 1)</span>² <span>= 0  ... square root both sides to eliminate the squared binomial
</span>√(-2x - 1)² = √0  ... simplify; the square is canceled out and the root of 0 brings you back to 0
-2x - 1 = 0  ... solve like a two-step equation
-2x = 1
x = -1/2 is your x-value.
3 0
3 years ago
Read 2 more answers
1. What percent of 58 is 18?
malfutka [58]

In order to find the answer you will have too divide 58 by 18 and then divide what you get from that by 100 to get your answer.

100%/x%=58/18

(100/x)*x=(58/18)*x    

100=3.22222222222*x      

(3.22222222222) to get x

100/3.22222222222=x

x=31.0344827586

Therefore your answer is "31%."

Hope this helps.

8 0
3 years ago
How do I do this?<br>*Look at the directions in the photo*​
lora16 [44]

Answer:

Area\ of\ material\ required\ for\ the\ first\ box=384\ inches^2\\Area\ of\ material\ required\ for\ the\ second\ box=486\ inches^2\\Area\ of\ material\ required\ for\ the\ first\ box=600\ inches^2\\Total\ Area\ of\ material\ required=1470\ inches^2

Step-by-step explanation:

We\ are\ given:\\Diameter\ of\ the\ first\ volleyball=8\ inches \\Diameter\ of\ the\ second\ volleyball=9\ inches\\Diameter\ of\ the\ third\ volleyball= 10\ inches.\\Hence,\\We\ know\ that,\\If\ the\ side\ of\ the\ cube\ box\ is\ s, it's\ Total\ Surface\ Area\ =No.\ of\\ faces\ in\ a\ regular\ polyhedron\ *Area\ of\ each\ face\ of\ the\ polyhedron=6*s^2=6s^2\\Hence,\\Lets\ apply\ this\ equation\ in\ finding\ the\ area\ of\ material\ required\ for\ the\\ three\ cases.\\

As\ the\ volleyball\ should\ wholly\ fit\ into\ the\ box,\ the\ diameter\ of\ the\\ volleyballs\ would\ be\ the\ side\ of\ the\ cube\ box.\\Hence,\\For\ the\ first\ volleyball,\\Diameter\ of\ the\ first\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ first\ volleyball=8\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ first\ box=6s^2=6*8*8=384\ inches^2

For\ the\ second\ volleyball,\\Diameter\ of\ the\ second\ volleyball=9\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ second\ volleyball=9\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ second\ box=6s^2=6*9*9=486\ inches^2

For\ the\ third\ volleyball,\\Diameter\ of\ the\ third\ volleyball=8\ inches\\Hence,\\Side\ of\ the\ cubical\ box\ for\ the\ third\ volleyball=10\ inches.\\Hence,\\The\ Total\ Surface\ Area\ of\ the\ third\ box=6s^2=6*10*10=600\ inches^2

Hence,\\If\ you\ are\ asked\ the\ Total\ Area\ to\ make\ all\ the\ boxes,\\ you\ just\ add\ them\ together.\\Hence,\\Total\ Area\ of\ Material\ required\ to\ make\ the\ three\ boxes=384+486+600=1470\ inches^2

7 0
3 years ago
Six friends are going to sit together in a roller coaster car that has six seats in how many different arrangements can they sit
Schach [20]
They can sit in 6 different arrangements
8 0
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