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Harrizon [31]
2 years ago
14

Ben and Arnoldo are sharing snacks. They have peanut treats and coconut treats. Ben ate 2 of the peanut treats and 4 of the coco

nut treats for a total of 160 calories. Arnoldo ate 3 of the peanut treats and 2 of the coconut treats for a total of 140 calories. They wrote the system below to represent the number of calories there are in the two types of treats.
2 x + 4 y = 160. 3 x + 2 y = 140.

They found the solution to be (30, 25). How many calories are in each treat?
There are 25 calories in each peanut treat and 30 calories in each coconut treat.
There are 30 calories in each peanut treat and 25 calories in each coconut treat.
There are 28 calories in each peanut treat and 28 calories in each coconut treat.
There are 55 calories in each peanut treat and 55 calories in each coconut treat.
Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0

the answer is 21 it really not it just I have to do this for this app that won't give me these for answers

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Help me math gods helpppp meme
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the 3rd one from top

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i am not 42 but i am an EVEN number. i am more than 25 but less than 50. i am a multiple of 6 but do not have a digit of 3.
sertanlavr [38]
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What is the cross-sectional area of a cement pipe 2 in. thick with an inner diameter of 5 ft? Use pie 3.14.
Paul [167]

Answer:

1.60 ft^{2}

Step-by-step explanation:

Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.

i.e Area = \pir^{2}

So that,

for the inner part of the pipe,

r = \frac{diameter}{2}

 = \frac{5}{2}

 = 2.5 feet

Area of the inner part of the pipe = \pir^{2}

                                 = 3.14 x (2.5)^{2}

                                 = 19.625

Are of the inner part of the pipe is 19.63 ft^{2}.

Total diameter of the pipe = 5 + 0.2

                                           = 5.2 feet

r = \frac{5.2}{2}

 = 2.6 feet

Area of the pipe = \pir^{2}

                            = 3.14 x (2.6)^{2}

                            = 21.2264

Area of the pipe is 21.23 ft^{2}.

Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe

                                           = 21.2264 - 19.625

                                           = 1.6014

The cross sectional area of the cement pipe is 1.60 ft^{2}.

6 0
2 years ago
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