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barxatty [35]
3 years ago
14

HELPPPPPP HELPPPPP ANYONE PLEASEEEEEEE

Mathematics
2 answers:
labwork [276]3 years ago
8 0
Just use quiz lit and it’ll give you all the answers you need for your answers. Ok. Just
nasty-shy [4]3 years ago
6 0

Answer:

Step-by-step explanation:

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Help with these questions please!
Alisiya [41]

Answer:

1.  16

2.  -4

Step-by-step explanation:

First factor the expression

lim x→1  (x^3 + 5x^2 + 3x-9)/(x-1)

lim x→1  (x-1) (x+3)^2/(x-1)

Canceling the x-1  in the top and bottom

lim x→1   (x+3)^2

Let x=1

lim x→1   (1+3)^2 = 4^2 = 16


2.  lim x→0 (x^2 -6x+8) /(x-2)          

First factor the expression

    lim x→0 (x-4) (x-2) /(x-2)        

Canceling the x-2  in the top and bottom

lim x→0 (x-4)

Let x=0

lim x→0   (0-4) = -4

Filling in the table

x     -.1      -.01       -.001     .001     .01     .1

f(x) -4.1  -4.01    -4.001   -3.999   -3.99  -3.9

4 0
3 years ago
Read 2 more answers
Solve each formula for the specified variable​
lord [1]

Answer:

\frac{A-2wh}{2(w+h)}=l

Step-by-step explanation:

We have to find the formula for the value of 'l'.

So, we will isolate 'l' on one side of the formula.

A = 2lw + 2lh + 2wh

A = 2l(w + h) + 2wh

A - 2wh = 2l(w + h) + 2wh - 2wh

A - 2wh = 2l(w + h)

\frac{A-2wh}{2(w+h)}=\frac{2l(w+h)}{2(w+h)}

\frac{A-2wh}{2(w+h)}=l

Therefore, formula for 'l' will be,

\frac{A-2wh}{2(w+h)}=l

4 0
3 years ago
A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
I need help i dont know the answers
Arlecino [84]

Answer: Change the number: 36

To:48

Step-by-step explanation:

12x2 is 24 but 24 x 2 isn’t 36

5 0
3 years ago
Evaluate the expression. ab if a = 6 and b = 7
Misha Larkins [42]

Answer:

42

Step-by-step explanation:

6x7=42

4 0
3 years ago
Read 2 more answers
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