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grin007 [14]
3 years ago
10

What is the value of Z?

Mathematics
1 answer:
jasenka [17]3 years ago
5 0

Answer:

2

Step-by-step explanation:

2(z)+2 = 4

2z = 2 x 2 = 4

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Pls help me! (more info in photo)
goldfiish [28.3K]

Answer:

x+ 3/2y= 15

Step-by-step explanation:

8x+12y=120

To put the equation into standard form, the leading coefficient has to be 1. So, divide the whole equation by 8.

x+ 3/2y= 15

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3 years ago
How do you turn cm into mm
bazaltina [42]
Multiply the centimeters by 100
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3 years ago
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Find the next two terms in the pattern 100,98,94,88,80…
olga_2 [115]

Answer:

its 70 and 58

Step-by-step explanation:

The pattern: -2, -4, -6, -8, -10, -12...

5 0
2 years ago
Line segment MN is graphed in the first and second quadrants of a coordinate plane. The segment is translated 2 units up, then r
Ksju [112]

Answer:

Step-by-step explanation:

Since the line segment is only being translated and reflected it would still maintain its length. This is pretty much the only characteristic that would remain the same as te original line segment. It would not maintain the same x-axis positions for both endpoints of the line segment. This is because when it is translated 2 units up it is only moving on the y-axis and not the x-axis. But when it is reflected over the y-axis the endpoints flip and become the opposite values.

6 0
3 years ago
How to do composition of functions​
KengaRu [80]
<h2><u><em>If you rather have the link to get this info lmk!!</em></u></h2>

Example: f(x) = 2x+3 and g(x) = x2

"x" is just a placeholder. To avoid confusion let's just call it "input":

f(input) = 2(input)+3

g(input) = (input)2

Let's start:

(g º f)(x) = g(f(x))

First we apply f, then apply g to that result:

Function Composition - (g º f)(x) = (2x+3)2

What if we reverse the order of f and g?

(f º g)(x) = f(g(x))

First we apply g, then apply f to that result:

Function Composition - (f º g)(x) = 2x2+3

We get a different result!  When we reverse the order the result is rarely the same.  So be careful which function comes first.

<h2 />
5 0
3 years ago
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