A square has 4 sides of equa length
the perimiter is 4 times the side, or P=4s where s=length of 1 side
the area is length times witdth, but since the length=width, area=s² where s is the length of one side
so express A=s² in terms of P when P=4s
solve for s first in P=4s
P=4s
divide both sides by 4

subsitute

for s in the other eqaution



in terms of the perimiter, the area is
Answer:
3 / 8
Step-by-step explanation:
From the tree diagram provided :
Required outcome = atleast two consecutive tails :
(HTT) ; (TTH) ; (TTT) = 3
TOTAL POSSIBLE OUTCOMES = 8
PROBABILITY = REQUIRED OUTCOME / TOTAL POSSIBLE OUTCOMES
HENCE ;
P(ATLEAST TWO TAILS IN A ROW) = 3 / 8
5x+2y=3
-5x on both sides
2y=3-5x
divide by 2 on both sides
y=3/2-5/2x
rewrite in order (optional depending on teacher)
y=-5/2x+3/2
Answer: Tresury department
Step-by-step explanation:
Step-by-step explanation:
area of the base is the area of the rectangle 5×12.
B = 5×12 = 60 in²
the height h is then the side going up from that base rectangle : 4 in.
the perimeter of the base (rectangle) is 2×length + 2×width
P = 2×12 + 2×5 = 24 + 10 = 34 in.