Answer:
(7u+1)(2u-5)
Step-by-step explanation:
miltiply the coefficient of u² and the integer -5 = -70
from basic intuition: factors are -35 and +2
(which when added gives -33 and multiplies to give 70)
14u² -35u +2u -5
7u(2u-5) +1(2u-5)
(7u+1)(2u-5)
The answer is 17/18.
You need to make the denominator the same on all the fractions.
Hope this helps.
1. Joe- 2+b (or 2+1b)
Micheal- 2b
2. Joe- 2+10=12
Micheal- 2x10=20
3. one distributes and the other just adds regularly.
We know that it is a 7th degree polynomial with 4 terms.
In order to find this, we must first do the subtraction.
6x^6 − x^3 y^4 − 5x y^5 - (4x^5 y + 2x^3 y^4 + 5x y^5)
Then we can simplify using like terms.
6x^6 - 4x^5y - 3x^3y^4 - 10xy^5
You'll see the 4 terms in the final answer. You'll also see that the term with the highest number of variables is -3x^3y^4, which has 3 x's and 4 y's for a total of 7. This makes this a 7th degree polynomial.
