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BigorU [14]
3 years ago
11

What are roots of the equation -90=x (x-18)

Mathematics
1 answer:
daser333 [38]3 years ago
4 0

Answer:

-90=x(x-18)

-90=x^{2}-18x

0=x^{2}-18x+90

x=9+3i   or   9-3i

Step-by-step explanation:

you need to use quadratic formula and you will find square root a negative ( -9 ), which is an imaginary no.

square root (-9) = 3i

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In two or more complete sentences, describe a real world situation that can be modeled by the inequality and solve the inequalit
sp2606 [1]
Brittany was playing with 11 marbles on the ground and her friend Natasha was playing with 23 so they couldn't play a game together. then Brittany's friend lent her some amount of marbles that made it so they could play together. what expression could you use to describe this problem?

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3 years ago
If sin A = 3/8, find the value of cosec A - sec A.​
alexira [117]

Answer:

\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}

\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

6 0
2 years ago
The expression 21m−49n factored using the GCF
rewona [7]
Here is my work for the problem. Hope this helps!

5 0
3 years ago
Read 2 more answers
Q # 8 please helme to resolve
kondor19780726 [428]

Sequence 1,5,9,13,...

A(0) = 1 +4x0=1

A(1) =1 + 4x1 = 5

A(2) = 1+ 4x2= 9

A(3) = 1 +4x3=13

A(n)= 1+4n   A(n-1) = 1+4(n-1) =1+4n-4= - 3+4n

A(n) - A(n-1) = (1+4n) - (-3=4n) = 4

A(n) = A(n-1) +4; 29 is the answer

4 0
3 years ago
HURRY INVERSE OF A FUCTION​
Anon25 [30]
Here is how we get the answer....
First, replace f(x) with y . ...
Replace every x with a y and replace every y with an x .
Solve the equation from Step 2 for y . ...
Replace y with f−1(x) f − 1 ( x ) . ...
Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
6 0
3 years ago
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