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Talja [164]
3 years ago
7

Graph the equation. y= - 2x + 4

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0

a point on the y-axis at positive 4

for the rest of the points go right 1 down 2

and left 1 up 2

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What is the slope of the line with equation y-3=-1/2(x-2)?
dezoksy [38]

Answer:

5.9(86)

Step-by-step explanation:

5 0
3 years ago
If the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola, find an equation for the parabola. Write
STALIN [3.7K]

Answer:

y=-1(x-2)^2+3

Step-by-step explanation:

W have been given that the vertex of a parabola is at (2, 3) and the point (0, -1) is also on the parabola. We are asked to find the equation of parabola in the form y=(x-h)^2+k.  

We know that vertex form of parabola in form y=a(x-h)^2+k, where (h,k) in vertex of parabola.  

Upon substituting coordinates of vertex, we will get:

y=a(x-2)^2+3

To find the value of a, we will substitute coordinates of point (0, -1) as:

-1=a(0-2)^2+3

-1=a(4)+3

-1=4a+3

-1-3=4a+3-3

-4=4a

\frac{-4}{4}=\frac{4a}{4}

-1=a

Therefore, our required equation would be y=-1(x-2)^2+3.

3 0
3 years ago
Help---------------​
Fiesta28 [93]

Answer:

C. (f - g)(x) = 3ˣ - 2x + 14

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Function Notation
  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3ˣ + 10

g(x) = 2x - 4

(f - g)(x) is f(x) - g(x)

<u>Step 2: Find (f - g)(x)</u>

  1. Substitute:                    (f - g)(x) = 3ˣ + 10 - (2x - 4)
  2. Distribute -1:                 (f - g)(x) = 3ˣ + 10 - 2x + 4
  3. Combine like terms:    (f - g)(x) = 3ˣ - 2x + 14
8 0
3 years ago
Use the segment addition postulate to write three equations using the diagram below
creativ13 [48]

Answer:

PQ + QR = PR => equation 1

RS + ST = RT => equation 2

PR + RT = PT => equation 3

Step-by-step explanation:

Points P, Q, R, S, and T are collinear therefore, the following equations can be written based on the segment addition postulate:

PQ + QR = PR => equation 1

RS + ST = RT => equation 2

PR + RT = PT => equation 3

More equations can actually be written from the diagram given using the segment addition postulate. Such as:

PQ + QR + RS + ST = PT

8 0
3 years ago
Can anybody help me out here it’s pre alegbra
lora16 [44]

Answer:

15 km

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2

Draw a triangle with 12 for x direction and 9 for y direction

The distance is the connecting line which is the hypotenuse

12^2 + 9^2 = c^2

144+81 = c^2

225 = c^2

Taking the square root of each side

sqrt(225) = sqrt(c^2)

15 =c

5 0
3 years ago
Read 2 more answers
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