Answer:
Frequency of allele A1- 0.41
Explanation:
In Hardy weinberg equilibrium,
P refers to the dominant allele
q refers to the recessive allele
The allele frequency will be p+q=1
The genotypic frequency is- P²+q²+2pq=1
P²= genotype of dominant trait ( A1A1)- 77
2pq= genotype of heterozygotes (2pq)- 65
q²= genotype of recessive trait (A2A2)- 123
Total number of offsprings= 77+ 65+ 123
= 265
Now to calculate allele frequency of A1=
= 77/265 + 1/2( 65//265)
= 0.290+ 0.122
= 0.413
Thus, 0.41 is correct.
Answer:
D
Explanation:
You can immediately eliminate B and C. So between A and D, D is the best answer.
Answer:
No more reactions occurs.
Explanation:
The activity of other metabolic pathways also change in response to the proton which enters mitochondria without passing through ATP synthase because ATP synthase is responsible for the production of ATP molecules from proton. If this ATP is not produced no further reactions occurs in the cell. This ATP is used by the cells in various activities so if the proton does not pass through ATP synthase then no energy in the form of ATP is present for other metabolic pathways of the cells.
