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mixer [17]
3 years ago
15

2x(27x+5) Evaluate this please

Mathematics
1 answer:
igomit [66]3 years ago
6 0

Answer:

54x^2 + 10x

Step-by-step explanation:

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Solve the inequality 0<5x-2<8
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×= 2 this is what I got as a result to my equations

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7. There are approximately 1.2 x 108 households
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Q # 1 simplify the expression
Agata [3.3K]
<u>Answer</u>

95,040

<u>Explanation</u>
The interpretation of this expression is; the number of permutation of 5 objects out of 12.

12P5 = 12!/(12-5)!

         =12!/7!
         =(12×11×10×9×8×7×6×5×4×3×2×1)/(7×6×5×4×3×2×1)

         =12×11×10×9×8
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5 0
3 years ago
Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim
andreev551 [17]

Answer:

p_v =P(t_{74}    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation    

\bar X=18.81 represent the average lateral recumbency for the sample    

s=8.4 represent the sample standard deviation    

n=75 sample size    

\mu_o =20 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to apply a left tailed  test.  

What are H0 and Ha for this study?    

Null hypothesis:  \mu \geq 20  

Alternative hypothesis :\mu < 20  

Compute the test statistic  

The statistic for this case is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227

The degrees of freedom are given by:

df=n-1=75-1=74    

Give the appropriate conclusion for the test  

Since is a one side left tailed test the p value would be:    

p_v =P(t_{74}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0
3 years ago
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