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When factoring

gtnhenbr [62]

Answer:

What goes in the blank is 2

Step-by-step explanation:

In this question, we want to know what goes into the bracket when factorizing the expression above.

What we have a problem with is the terms x^2 - 4x + 4

We can rewrite this as;

x^2 -2x - 2x + 4

x(x-2) -2(x - 2)

That would thus be (x-2)^2

What goes into the bracket is thus the number 2

3 0

3 years ago

Read 2 more answers

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$

$\text{Distance traveled by train B}=70\times 5 \text{ miles}$

$\text{Distance traveled by train B}=350\text{ miles}$

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0

3 years ago

Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).

mojhsa [17]

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)

we put a^2 = 81x^8 and b^2 = 1 giving

a = 9x^4 and b = 1, so:

81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

4 0

2 years ago

Help please it’s for a test I’m so clueless!!!!!!

kumpel [21]

Answer:

h=12 A=144 sq. cm.

Step-by-step explanation:

pythagoream therom:

9^2+h^2=15^2

81+h^2=225

h^2=225-81

h^2=144

Sq. rt h^2=sq. rt 144

h=12cm

1/2(b1+b2)h

1/2(5+19)12

1/2(24)12

1/2(288)

a=144

6 0

2 years ago

In a murder investigation, the temperature of a corpse was 32.5 degrees C at 1:30 pm and 30.3 degrees C an hour later. Normal bo

svp [43]

Let $T(t)$ be the temperature of the body $t$ hours after 1:30 PM. Then $T(0) = 32.5$ and $T(1) = 30.3$ .

Using Newton's Law of Cooling, $\dfrac{dT}{dt} = k(T - T_s)$ , we have $\dfrac{dT}{dt} = k(T-20)$ . Now let $y = T - 20$ , so
$y(0) = T(0) - 20 = 32.5 - 20 = 12.5$ , so $y$ is a solution to the initial value problem $dy/dt = ky$ with $y(0) = 12.5$ .
By separating and integrating, we have $y(t) = y(0)e^{kt} = 12.5e^{kt}$ .

$y(1) = 30.3 - 20\ \Rightarrow\ 12.5e^{k(1)} = e^{k} = \frac{10.3}{12.5}\ \Rightarrow \\
k = \ln \frac{10.3}{12.5}
$

$y(t) = 37 - 20\ \Rightarrow\ 12.5e^{kt} = 17\ \Rightarrow\ e^{kt} = \frac{10.3}{12.5} \ \Rightarrow \\ \\
kt = \ln \frac{10.3}{12.5}\ \Rightarrow\ t = \left( \ln \frac{17}{12.5} \right)/ \frac{10.3}{12.5} \approx -1.588 \mathrm{\ h}$

≈ 95 minutes. Thus the murder took place about 95 minutes before 1:30 PM, or 11:55 AM.

6 0

3 years ago