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3 years ago

14

Questol 2 UI IU

2 answers:

castortr0y [4]3 years ago

6 0

The answer would be D because an indulgence is when you pay to forgive your sin

Gnesinka [82]3 years ago

4 0

The correct answer is D. A man pays a religious leader to forgive him for lying.

Explanation:

In religion, the term indulgence refers to an action that reduces or compensates sins, this includes praying, performing good works or paying some money to the church. Indulgences are mainly used as part of Catholic religions in which sinners are punished after death in the purgatory or hell, and therefore through indulgences individuals can avoid this punishment.

According to this, the action that is an example of indulgence is "A man pays a religious leader to forgive him for lying" because this includes an individual paying money to compensate his sins and therefore avoid being punished in the purgatory or hell later.

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Ursula tosses two six-sided number cubes and MULTIPLIES the numbers rolled. Which of these is a list of the outcomes of the two

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Answer:

3,4,5,6,7,8

Step-by-step explanation:

sum of 2 with other possible numbers:

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3, 4, 5, 6, 7, 8

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3 years ago

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3 years ago

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2 years ago

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Calculate the equation of a line passing through C(4;7) and D(9;17)

Ludmilka [50]

Answer:

it would be 10/5 or 2

Step-by-step explanation:

y2-y1/x2-x1

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2

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2 years ago

Let X denote the temperature (degree C) and let Y denote thetime in minutes that it takes for the diesel engine on anautomobile

BlackZzzverrR [31]

Answer:

Step-by-step explanation:

Given $f_{XY} (x,y) = c(4x + 2y +1) ; 0 < x < 40\,and\, 0 < y$

a)

we know that $\int\limits^\infty_{-\infty}\int\limits^\infty_{-\infty} {f(x,y)} \, dxdy=1$

therefore $\int\limits^{40}_{-0}\int\limits^2_{0} {c(4x+2y+1)} \, dxdy=1$

on integrating we get

c=(1/6640)

b)

$P(X>20, Y>=1)=\int\limits^{40}_{20}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

on doing the integration we get

=0.37349

c)

marginal density of X is

$f(x)=\int\limits^2_{0} {\frca{1}{6640}(4x+2y+1)} \, dy$

on doing integration we get

f(x)=(4x+3)/3320 ; 0<x<40

marginal density of Y is

$f(y)=\int\limits^{40}_{0} {\frca{1}{6640}(4x+2y+1)} \, dx$

on doing integration we get

$f(y)=\frac{(y+40.5)}{83}$

d)

$P(01)=\int\limits^{40}_{0}\int\limits^2_{1} {\frca{1}{6640}(4x+2y+1)} \, dxdy$

solve the above integration we get the answer

e)

$P(X>20, 0$

solve the above integration we get the answer

f)

Two variables are said to be independent if there jointprobability density function is equal to the product of theirmarginal density functions.

we know f(x,y)

In the (c) bit we got f(x) and f(y)

f(x,y)cramster-equation-2006112927536330036287f(x).f(y)

therefore X and Y are not independent

4 0

3 years ago