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3 years ago

What number is 64% of 120? i don’t need solutions , just answer please and thank you !!! ❤️

Mathematics

1 answer:

Ivenika [448]3 years ago

4 0

Answer:

76.80

Step-by-step explanation:

Hi there !

100% .............. 120

64% .....................x

x = 64×120/100

= 7680/100

= 76.80

Good luck !

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61 ones times 1/10 =? or = 61 ones*1/10=?

aniked [119]

61 x (1/10)=

Or 61 x .1

The answer is 6.1

8 0

3 years ago

What is the slope-intercept form for a line that passes through (4,3) and is parallel to x=0

nikitadnepr [17]

Answer:

x=4

Step-by-step explanation:

x=0 is an undefined slope(straight line vertically)

We need the line to pass through the point (4,3)

So, we just take the x coordinate from the equation and make it also have an undefined slope.

x = 4

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4 years ago

A freight train departs from one train station to its destination at a constant speed. Suppose the distance the train is from th

barxatty [35]

Answer:

108 miles

Step-by-step explanation:

Given the points (0.5, 135) and (2,81)

Diatnce between two points :

D = √(x2 - x1)² + (y2 - y1)²

X1 = 0.5 ; y1 = 135 ; x2 = 2 ; y2 = 81

D = √(2^2 - 0.5^2) + (81^2 - 135^2)

D = √(4 - 0.25) + (6561 - 18225)

D = √3.75 −11664

D = 107.98263

D = 108 miles

6 0

3 years ago

Simplify the expression state any excluded values 2a^2-4a+2 --------------- 3a^2-3

chubhunter [2.5K]

Answer:

The simplified form is $\dfrac{2(x-1)}{3(x+1)}$ .

$x =1$ is the excluded value for the given expression.

Step-by-step explanation:

Given:

The expression given is:

$\dfrac{2a^2-4a+2}{3a^2-3}$

Let us simplify the numerator and denominator separately.

The numerator is given as $2a^2-4a+2$

2 is a common factor in all the three terms. So, we factor it out. This gives,

$=2(a^2-2a+1)$

Now, $a^2-2a+1=(a-1)(a-1)$

Therefore, the numerator becomes $2(a-1)(a-1)$

The denominator is given as: $3a^2-3$

Factoring out 3, we get

$3(a^2-1)$

Now, $a^2-1$ is of the form $a^2-b^2=(a-b)(a+b)$

So, $a^2-1=(a-1)(a+1)$

Therefore, the denominator becomes $3(a-1)(a+1)$

Now, the given expression is simplified to:

$\frac{2a^2-4a+2}{3a^2-3}=\frac{2(x-1)(x-1)}{3(x-1)(x+1)}$

There is $(x-1)$ in the numerator and denominator. We can cancel them only if $x\ne1$ as for $x=1$ , the given expression is undefined.

Now, cancelling the like terms considering $x\ne1$ , we get:

$\dfrac{2a^2-4a+2}{3a^2-3}=\dfrac{2(x-1)}{3(x+1)}$

Therefore, the simplified form is $\dfrac{2(x-1)}{3(x+1)}$

The simplification is true only if $x\ne1$ . So, $x =1$ is the excluded value for the given expression.

8 0

4 years ago

What is the value of x 55,105 A.50 B.20 C.160 D.55

Ann [662]

Answer:

c)55

Step-by-step explanation:

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3 years ago