Place value of 2 in Decimal 137.5428

If the sides of a square are lengthened by 7 feet, the area becomes 121 square feet. How long is a side of the original square?

Bogdan [553]

Square root of 121 is 11.
11-7=4
A side of the original square is 4 feet.

5 0

3 years ago

Read 2 more answers

Find the x and y intercepts for the following equation. 2x– 7y=-14

Kisachek [45]

Answer:

C: Xint = 2, Yint. = -7

Step-by-step explanation:

Given the equation, 2x - 7y = -14:

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates (0, b). It is also the value of y when x = 0. To solve for the y-intercept, set x = 0:

2x - 7y = -14

2(0) - 7y = -14

0 - 7y = -14

-7y = -14

Divide both sides by -7 to solve for y:

-7y/-7 = -14/-7

y = 2

Therefore, the y-intercept = 2.

Next, the x-intercept is the point on the graph where it crosses the x-axis, and has coordinates, (a, 0). To find the x-intercept, set y = 0 and substitute into the given equation:

2x - 7y = -14

2x - 7(0) = -14

2x - 0 = -14

2x = -14

Divide both sides by 2 to solve for x:

2x/2 = -14/2

x = -7

x-intercept = -7.

Therefore, the correct answer is C: Xint = 2, Yint. = -7

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7 0

3 years ago

Check What is the slope of the line on the graph?

katen-ka-za [31]

Slope: the tilt. it equals rise over run. so 1/2

7 0

4 years ago

12 x − 15 = 6 − 3 x

11Alexandr11 [23.1K]

Answer:

x= 7/5 (1 2/5 or 1.4)

Step-by-step explanation:

Move the variable to the left-hand side and change its sign.

12x-15+3x=6

Move the constant to the right-hand side and change its sign.

12x+3x=6+15

Collect like terms.

15x=21

Divide both sides of the equation by 15.

x=7/5 (1 2/5 or 1.4)

5 0

3 years ago

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

5 0

3 years ago