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OLEGan [10]
3 years ago
8

#1 plz thx!!!!!!!!!!

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
5 0
We have to use pythagorean theorem. The equation is a^{2} + b^{2} = c^{2} so we plug in the numbers (hypothenuse is always C in the equation) a^{2} + 8^{2} =10^{2} now we solve:

a^{2} +64=100 Exponents 

a^{2} =36 Subtract

a=6 Square Root

x=6 Answer
You might be interested in
Find the inflection point of the function of f(x) = x³ -6x² +12x
Wewaii [24]

Points of inflections are zeroes of the second derivative. We have:

f(x)=x^3-6x^2+12x\implies f'(x)=3x^2-12x\implies f''(x)=6x-12

So, the second derivative equals zero if and only if

f''(x)=0\iff 6x-12=0 \iff 6x=12 \iff x=2

So, this is the only point of inflection of this function.

5 0
3 years ago
If two angles of a triangle have measures of 42° and 20°, what is the measure of the
iris [78.8K]

Answer:

118°

Step-by-step explanation:

the angle measures of a triangle will always add up to 180

so..

42+20=62

180-62=118

4 0
3 years ago
Read 2 more answers
I need help with this please
Nookie1986 [14]

Answer:

steps below

Step-by-step explanation:

3.2.1   AD = DB* sin 2 = DB * sin θ   .. DE // AB   ∠2= θ  ... (1)

By laws of sines:  DB / sin ∠5 = x / sin ∠4    

∠4 = θ-α     ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α

DB = (x*sin ∠5)/sin (θ-α)

     = (x* sin (90°+α)) / sin (θ-α)

AD = DB*sinθ

     = (x* sin (90°+α))*sinθ / sin (θ-α)

     = x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α)    .... sin90°=1, cos90°=0

     = x* cosα* sinθ / sin (θ-α)

3.2.2 Please apply Laws of sines to calculate the length

7 0
2 years ago
PLEASE HELP!!
Andre45 [30]

Answer:

I think the answer is c

Step-by-step explanation:

Because it says at most? am I right

8 0
3 years ago
Read 2 more answers
PLZ HURRY IT'S URGENT!!!!!!!
klasskru [66]

I think it would be C but that’s just my opinion

7 0
3 years ago
Read 2 more answers
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