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2 years ago

NEED HELP 6th GRADE MATH PLEASE HELP ASAP THIS IS A LATE ASSIGNMENT

Mathematics

1 answer:

lara [203]2 years ago

7 0

Answer:

± 42.25

Step-by-step explanation:

±6.5^2 = ±42.25

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Write the product in simplest form: 3w^4 * (-5w^2)

Grace [21]

$3w^{4} (-5w^{2} ) = -15w^{6}$

I think this is what you want? When multiplying with exponents, you either add or multiply the exponents.

When you multiply the exponent:

(x²)³ = $x^{6}$

$(3x^{4} )^{2}$ = 9 $x^{8}$

When you add the exponents:

(x²)(x³) = $x^{5}$

(x²)(x²) = $x^{4}$

$(x^{4} )(x^{3} ) = x^{7}$

5 0

3 years ago

Please help quick thank you

Luda [366]

Each square in the diagram is equal to the value of 1 while c isn't equal to the squares. Simply $1\neq c$ . Since there are 6 squares that means 1*6 = 6. The whole value of the squares is 6. While the rectangle value isn't known or defined as "c" and you have 3 rectangles the value of it would be 3*c which is 3c.

So the answer is C. 6+3c

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3 years ago

What is the volume, in cubic feet, of the cylinder below? 6 ft 8 ft

aksik [14]

Answer:

226.1946711 cubic ft

Step-by-step explanation:

volume of cylinder = πr²h

diameter (d)=6ft

r= d/2 = 6/2=3ft

h= 8ft

putting all values in the formula and calculating the volume

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2 years ago

F(x)=(4t^2-t) (t^3-8t^2+12) in product rule.

gavmur [86]

$\dfrac{d}{dt} [(4t^2-t)(t^3 -8t^2+12)]\\\\\\=(4t^2-t)\dfrac{d}{dt}(t^3-8t^2 +12) + (t^3 -8t^2 +12) \dfrac{d}{dt} (4t^2 -t)\\\\\\=(4t^2 -t)(3t^2-16t)+(t^3-8t^2+12)(8t-1)\\\\=12t^4-64t^3 -3t^3+16t^2+8t^4-64t^3+96t-t^3+8t^2-12\\\\=20t^4-132t^3+24t^2+96t-12$

6 0

2 years ago

In a class test, +4 marks were awarded for the correct answers and -1 mark for the wrong answers. Student scores 40 marks. If hi

nikklg [1K]

Step-by-step explanation:

Let y the number of wrong answers got.

$11( + 4) + ( - 1)y = 40 \\ 44 - y = 40 \\ - y = - 4 \\ y = 4$

∴ He got 4 wrong answers.

7 0

2 years ago