The solution of the given equation represented in the task content can be determined by first evaluating the LCM and hence is; y= 27.
<h3>What is the solution of the equation as given in the task?</h3>
The given equation is; (y-5)/2=(y+6)/3.
Hence, by multiplying the equation by 6, we have;
3(y-5) = 2(y+6)
3y -15 = 2y +12
y = 27.
Hence, it follows that the value of y which is a solution to the equation is; y = 27.
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Answer:
ASA
Step-by-step explanation: I'm not sure I had just found a key.
Answer:
x = 3, x = 0
Step-by-step explanation:
To solve these factored equations, just divide each part by zero and solve.
2x(x-3) = 0 → (x-3) = 0, and 2x = 0.
(x-3) = 0 → x - 3 + 3 = 0 + 3 → <u>x = 3.</u>
2x = 0 → 2x/2 = 0/2 → <u>x = 0.</u>
F(x) = (2x-1)(x+2)/ (x+2)
f(x) = 2x-1
f(-2) = 2(-2)-1
f(-2) = -5
let length of the rectangle be l
length is 6 cm longer than the width, w
l = w + 6
perimeter of rectangle is 72 cm
= 2l + 2w
substitute l = w + 6
2(w+6) + 2w = 72
4w + 12 = 72
4w = 60
x = 15
ans is C. 15 cm
