Ask question

Ask question

All categories

kakasveta [241]

2 years ago

10

0.5 (ug)^2 (Mm)^-3 is equivalent to ...... kg^2 cm^-3

1 answer:

aivan3 [116]2 years ago

6 0

Thanks tell the the answer he 78 I know this as 781 - is 780

You might be interested in

What is 3 and 5? And show how to solve plz

nataly862011 [7]

Answer:

3. 9n + 6 = 78

5. see below

Step-by-step explanation:

3.

Let the number of adults be n. Each adult ticket costs $9, so the cost of n adult tickets is 9n. There is only one child, and a child's ticket is $6, so the cost of the child's ticket is 6. Adding the costs, you get 9n + 6. The total cost is $78, but the expression representing the total cost is 9n + 6, so 9n + 6 must equal 78. That is the equation.

9n + 6 = 78

5.

Sam bought equal gifts for his two children. The two gifts had the same price, x. He received a discount of $125. How much did each of the two gifts cost before the discount?

5 0

3 years ago

bone-shaped treats are five for 3:50 at Shelly store in Sarah wants to buy 12 she set up and solve this proportion to find how m

Valentin [98]

Answer:

8.4 dollars

Step-by-step explanation:

The error is in the resolution of the proportion. In fact, the initial proportion is correct:

$\frac{5}{3.5}=\frac{12}{x}$

where x is the total cost. However, the following step of the resolution is wrong. In fact, the correct resolution is the following:

- Multiplying by x on both sides:

$\frac{5x}{3.5}=12$

- Multiplying by 3.5 no both sides:

$5 x = 12 \cdot 3.5 \\5x = 42$

And now we can find x:

$x=\frac{42}{5}=8.4$

So, the total cost is 8.4 dollars.

3 0

3 years ago

Read 2 more answers

Evaluate 4.7 j−6.8k when j=5 and k=3

oksano4ka [1.4K]

Answer:

3.1

Step-by-step explanation:

ok so

4.7j-6.8k J=5 k=3 plug in the values

4.7(5)-6.8(3)

23.5-20.4

3.1

8 0

2 years ago

Read 2 more answers

Which expression is equivalent

gtnhenbr [62]

Answer:

Option B is correct.

$\frac{81m^2n^5}{8}$ is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Step-by-step explanation:

Given expression: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Using exponents power:

$(ab)^n = a^nb^n$

$(a^n)^m = a^{nm}$

$a^m \cdot a^n = a^{m+n}$

Given: $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$

Apply exponent power :

⇒ $\frac{3^4 (m^{-1})^4(n^2)^4}{2^3(m^{-2})^3 n^3}$

⇒ $\frac{81 m^{-4}n^8}{8m^{-6}n^3} = \frac{81 m^{-4} \cdot m^6 n^8 \cdot n^{-3}}{8}$

⇒ $\frac{81 m^{-4+6} n^{8-3}}{8} = \frac{81 m^2 n^5}{8} = \frac{81m^2 n^5}{8}$

Therefore, the expression which is equivalent to $\frac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}$ is, $\frac{81m^2 n^5}{8}$

4 0

3 years ago

Read 2 more answers

Find the value of each variable

Lynna [10]

7.75 and 45 are the variables in this equation

8 0

2 years ago