Simplify the expression 7y + 4x - 2x + 8

Mathematics

2 answers:

choli [55]3 years ago

7 0

I believe it is 0 my dude =}}}

Korvikt [17]3 years ago

4 0

Answer:

thts gon be 7y+2x+8

Step-by-step explanation:

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beks73 [17]

The result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

<h3>How to evaluate the expression?</h3>

The expression is given as:

$\sin^2(\theta) * (1 + \cos(\theta))$

Express $\sin^2(\theta)$ as $1 - \cos^2(\theta)$ .

So, we have:

$\sin^2(\theta) * (1 + \cos(\theta)) = (1- \cos^2(\theta)) * (1 + \cos(\theta))$

Open the bracket

$\sin^2(\theta) * (1 + \cos(\theta)) = 1 + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Express 1 as cos°(Ф)

$\sin^2(\theta) * (1 + \cos(\theta)) = cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Hence, the result of expanding the trigonometry expression $\sin^2(\theta) * (1 + \cos(\theta))$ is $cos^0(\theta) + \cos(\theta) - \cos^2(\theta) - \cos^3(\theta)$

Read more about trigonometry expressions at:

brainly.com/question/8120556

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3 0

2 years ago

What is the slope of the line containing (-3, 5) and (6, -1)?

mario62 [17]

Answer:

-2/3

Step-by-step explanation:

The slope of a line can be represented as $\frac{y_{2} -y_{1} }{x_{2}- x_{1} }$ where (x1, y1) and (x2, y2) are points on the line. We can substitute the points given, (-3, 5) and (6, -1), to calculate the slope: