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3 years ago

HELLPPPP ANSWERRR AND EXPLAIN!!!!!

Mathematics

2 answers:

bixtya [17]3 years ago

5 0

Answer:

Step-by-step explanation:

This is because K and B don't share the same angle measurement. They both will be different numbers that must equal 180 degrees. With that K will be corresponding with J while B will be corresponding with D.

Hope this Helped

rodikova [14]3 years ago

5 0

No the angles are actually like a tad different I think so there not corresponding I’m sorry I just did this for points, lol so u don’t have to mark me brainliest if you don’t want to. Have a nice day!!

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Twenty six equals eight plus v

Mumz [18]

18. You can do this in a calculator. 26 - 8 = 18. v = 18.

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3 years ago

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If 3(11x-18y)=6(x+y)-3x-10y <br> what is the ratio of x to y?

exis [7]

Answer: 3:5

Step-by-step explanation:

33x-54y=6x+6y-3x-10y

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3 years ago

Given F(x)=1/x-4, g(x)=1/6-x. Find f+g(x).

Yakvenalex [24]

$\boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Explanation:</h2>

We are given two functions:

$f(x)=\frac{1}{4}x-4 \\ \\ g(x)=\frac{1}{6}-x$

So, we have to find $f(x)+g(x)$ which is the sum of these two functions:

$f(x)+g(x)=\frac{1}{x}-4+\frac{1}{6}-x \\ \\ \\ Let's \ call \ h(x)=f(x)+g(x) \\ \\ Simplifying: \\ \\ h(x)=\left(\frac{1}{x}-x)+(-4+\frac{1}{6}) \\ \\ \\ \\$

$Finally: \\ \\ \boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

<h2>Learn more:</h2>

Shifting graphs: brainly.com/question/10010217

#LearnWithBrainly

3 0

3 years ago

Can you please help me with this question

user100 [1]

Answer:

tbh im dumb so

Step-by-step explanation:

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3 years ago

If A2 = I, where I is the identity matrix, which matrix correctly represents matrix A?

natali 33 [55]

We know that $\boldsymbol{A^2}=\boldsymbol{A\times A}$

We also know that $\boldsymbol{I}=\begin{bmatrix} 1 &0 \\ 0&1 \end{bmatrix}$

Now, it has been given to us that $\boldsymbol{A^2}=\boldsymbol{I}$

Therefore, we will have to find the correct $\boldsymbol{A}$ from the given options and we find that when:

$\boldsymbol{A}=\begin{bmatrix} 3 &-2 \\ 4&-3 \end{bmatrix}$

then $\boldsymbol{A^2}=\boldsymbol{A\times A}=\begin{bmatrix} 3 &-2 \\ 4&-3 \end{bmatrix}\times \begin{bmatrix} 3 &-2 \\ 4&-3 \end{bmatrix}=\begin{bmatrix} 1 & 0\\ 0 & 1 \end{bmatrix}$

Therefore, from the above given options, Option C is the correct option.

Therefore, $\boldsymbol{A}=\begin{bmatrix} 3 & -2\\ 4 & -3 \end{bmatrix}$ is the correct answer.

7 0

3 years ago

HELLPPPP ANSWERRR AND EXPLAIN!!!!!​

HELLPPPP ANSWERRR AND EXPLAIN!!!!!