Question

Given F(x)=1/x-4, g(x)=1/6-x. Find f+g(x).

Answer 1

$\boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

Explanation:

We are given two functions:

$f(x)=\frac{1}{4}x-4 \\ \\ g(x)=\frac{1}{6}-x$

So, we have to find $f(x)+g(x)$ which is the sum of these two functions:

$f(x)+g(x)=\frac{1}{x}-4+\frac{1}{6}-x \\ \\ \\ Let's \ call \ h(x)=f(x)+g(x) \\ \\ Simplifying: \\ \\ h(x)=\left(\frac{1}{x}-x)+(-4+\frac{1}{6})$

$Finally: \\ \\ \boxed{f(x)+g(x)=\frac{1}{x}-x-\frac{23}{6}}$

Learn more:

Shifting graphs: brainly.com/question/10010217

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