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IRINA_888 [86]
3 years ago
8

****-2x^2(-5x^2+4x^3) in standard form?

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0
-2 x^{2} (-5 x^{2} +4 x^{3} )   Use distributive property

-2 x^{2} (-5 x^{2}) +-2 x^{2} (4 x^{3} )

10 x^{2+2} +-8 x^{2+3}

10 x^{4}+ -8 x^{5}

-8 x^{5}+ 10 x^{4}  <-answer
Lyrx [107]3 years ago
3 0
-2x^2(-5x^2+4x^3)=10x^4-8x^5
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Dmitrij [34]

Answer:

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Step-by-step explanation:

To find the roots, we set the equation equal to zero and factor.

x(x²+6x+5)=0           [factor]

x(x+1)(x+5)=0            [set each factor equal to 0]

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