Question

Can somebody help me on 23 and 24, it’s geometry

Answer 1

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Step-by-step explanation:

As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE

Question number 23:

Given

DS = 3x+10

SE = 6x-2

As the two segments are equal:

$DS = SE\\3x+10 = 6x-2$

Subtracting 10 from both sides

$3x+10-10 = 6x-2-10\\3x = 6x-12$

subtracting 6x from both sides

$3x -6x = 6x-6x-12\\-3x = -12$

Dividing both sides by -3

$\frac{-3x}{-3} = \frac{-12}{-3}\\x = 4$

Now

$DS = 3x+10\\= 3(4)+10\\= 12+10\\=22$

And

$SE = 6x-2\\= 6(4)-2\\= 24 - 2\\=22\\DE = DS+SE\\= 22+22\\=44$

Question No 24:

Given

DS = x+3

DE = 56

We know that:

$DS = \frac{1}{2}DE\\x+3 = \frac{56}{2}\\x + 3 = 28\\x = 28-3\\x = 25$

So

DS = $25+3 = 28$

As DS is 28, SE will also be 28

Hence,

Question 23:

x = 4

DE = 44

Question 24:

x = 25

SE = 28

Keywords: Bisector, Line segment

Learn more about line segments at:

• brainly.com/question/629998
• brainly.com/question/6208262

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