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3 years ago

If a car travels 90 km in 1 1/2 hours, how fast is it

Mathematics

1 answer:

Kazeer [188]3 years ago

5 0

Answer:

Step-by-step explanation:

just divide the distance with the time which is 90km/11/2 hours.

D/T

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How do you write 8.317 x10^6 in standard form

CaHeK987 [17]

Answer:

8.317 x 10^6 = 8,317,000

Step-by-step explanation:

You move the decimal over 6 places to the right because it's a positive number. If it were 10^-6 you would move the decimal over 6 places to the left.

5 0

3 years ago

An equiangular triangle has one side of length six inches. What is the height of the triangle, drawn from that side, to the near

tino4ka555 [31]

Answer:

The height of the triangle is 5.2 inches

Step-by-step explanation:

we know that

An <u>equiangular triangle</u> is a triangle where all three interior angles are equal in measure

Remember that an equilateral triangle has three equal sides and three equal interior angles

An equiangular triangle Is the same that an equilateral triangle. The measure of its interior angles is equal to 60 degrees

Let

h ----> the height of triangle

b ---> the length side of the triangle

Applying Pythagoras Theorem

$h^2=b^2-(b/2)^2$

we have

$b=6\ in$

substitute

$h^2=6^2-(6/2)^2$

$h^2=36-9$

$h^2=27$

$h=\sqrt{27}\ in$

$h=5.2\ in$

see the attached figure to better understand the problem

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3 years ago

Which system matches the graph below?

ioda

Answer:

(a)

Step-by-step explanation:

$y= -4^{x}$ and y = 2x - 3

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3 years ago

at a point P on the parabola x^2=4ay a normal PK is drawn. From vertex O, a perpendicular OM is drawn to meet the normal at M. S

saveliy_v [14]

<span>Answer: Its too long to write here, so I will just state what I did. I let P=(2ap,ap^2) and Q=(2aq,aq^2) But x-coordinates of P and Q differ by (2a) So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2) So Q=(2a(p-1), aq^2) which means, 2aq = 2a(p-1) therefore, q=p-1 then I subbed that value of q in aq^2 so Q=(2a(p-1), a(p-1)^2) and P=(2ap,ap^2) Using these two values, I found the midpoint which was: M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 ) then x = a(2p-1) rearranging to make p the subject p= (x+a)/2a</span>

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3 years ago

Your answer should be a polynomial in standard form (x-2)(x-1)= ?

fredd [130]

The answer is x squared -3x+2

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3 years ago