All categories

3 years ago

If A > B, where on the number line will A appear?

Mathematics

1 answer:

MAVERICK [17]3 years ago

5 0

Answer:

It will apear right after B and we can see it on the right side of B .

You might be interested in

A rectangular room measures 20 m long and 15 m wide. Work out the measurer for a scale drawing of the room using a scale of 1 cm

jonny [76]

20 / 2 = 10
15 / 2 = 7.5

10cm by 7.5cm

Hope this helps

8 0

3 years ago

Which is equivalent to 32 + 16

Scrat [10]

Answer:

8(4+2)

Step-by-step explanation:

Hi there! We know that 32+16=48 so all we have to do is find a expression that equals 48. 8(4+2)=48. 8(24+8)=256. 7(4+2)=42. 7(24+8)=224. Therefore, the expression that is equivalent to 32+16 is 8(4+2).

4 0

3 years ago

Read 2 more answers

Find the linear equation of the plane through the origin and the points (5,2,2) and (6,−1,1). equation:

Aleks [24]

The cross of the position vectors is
.. [5, 2, 2] × [6, -1, 1] = [4, 7, -17] . . . . . the normal vector of the desired plane

Since the origin is a point in the plane, its equation can be written as
.. 4x +7y -17z = 0

3 0

4 years ago

What is the quotient?StartFraction (negative 3) Superscript 0 Over (negative 3) squared EndFractionNegative 9StartFraction 1 Ove

Diano4ka-milaya [45]

Answer:

the answer is 1/9 in decimal for 0.1

Step-by-step explanation:

4 0

3 years ago

Two towns are 1,100 miles apart. A group of hikers Starts from each town and walks down the trail toward each other. They meet a

OLga [1]

Answer:

3.54 and 1.04

Step-by-step explanation:

Given:

Two towns are 1,100 miles apart.

A group of hikers Starts from each town and walks down the trail toward each other..

They meet after a total hiking time of 240 hours.

If one group travels 2 1/2 mile per hour slower than the other group.

Question asked:

Find the rate of each group.

Solution:

Let speed of faster hiker = $x\ mph$

Speed of slower hiker = $x-\frac{5}{2}\ mph$

As we know:

$Distance=speed\times time$

Total distance between two town = Total combined speed of both hikers $\times$ Total combined time taken

$1100=(x+x-\frac{5}{2} )\times240\\ \\ Dividing\ both\ sides\ by\ 240\\ \\ 4.58=(x+x-\frac{5}{2} )\\ \\ 4.58=2x-\frac{5}{2} \\ \\Adding\ both\ sides\ by\ \frac{5}{2} \\ \\ 4.58+ \frac{5}{2}=2x- \frac{5}{2}+ \frac{5}{2}\\ \\ \frac{2\times4.58+5}{2} =2x\\ \\ \frac{14.16}{2} =2x\\ \\ By \ cross\ multiplication\\ \\ 2\times2x=14.16\\ \\ 4x=14.16$

$By\ dividing\ both\ sides\ by \ 4\\ \\ x=3.54\ miles\ per\ hour$

Speed of faster hiker = $x\ mph$ = 3.54 miles per hour.

Speed of slower hiker = $x-\frac{5}{2}\ mph$ =

$3.54-\frac{5}{2} =3.54-2.5=1.04\ miles\ per\ hour$

Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.

8 0

3 years ago