Answer:
First term: 5
Fourth term: 5 1/2
Tenth term: 6 1/2
Step-by-step explanation:
Let's find the first, fourth and tenth terms of the arithmetic sequence described by the given rule:
A(n) = 5 + (n-1) (1/6)
First term:
A(1) = 5 + (1-1) (1/6)
A(1) = 5 + (0) (1/6)
A(1) = 5
Fourth term:
A(4) = 5 + (4-1) (1/6)
A(4) = 5 + (3) (1/6)
A(4) = 5 + 3/6 = 5 3/6 = 5 1/2 (simplifying)
Tenth term:
A(10) = 5 + (10-1) (1/6)
A(10) = 5 + (9) (1/6)
A (10) = 5 + 9/6 = 6 3/6 = 6 1/2 (simplifying)
A. Yes you are correct that the gradient at any point is 3/(3x-1). However at point P it would be 3/(3*2-1)=2/5
b. The gradient of the normal would therefore be -5/2
We can use the general formula of an equation to get y-ln(5)=-5/2 (x-2)
Now multiply both sides by 2 to get:
2y-2ln(5)=-5x+10
Now when it crosses the x axis we know that y=0 therefore:
5x=10+2ln(5)
Therefore:
x=2+2/5 ln(5) when y=0
You could find an estimate of this number to be 2.64 (3sf) but this might not be sufficient
Your answer would be C. 6.07 × 10^24.
This is because to add numbers in standard form, we need to get their (×10^x) to be the same, as in, we need to get 7 × 10^22 to be [value] × 10^24.
To convert ×10^22 to ×10^24, we need to divide 7 by 100, as 0.07 × 10^24 = 7 × 10^22.
Now that we have them both with the same power, we can add 6 to 0.7 to get 6.07 × 10^24.
I hope this helps! Let me know if you have any questions because my explanation was a bit strange :)
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