In the liner equation shown which variable represent the output values Y= MX + b
1 answer:
You might be interested in
Answer:
0.40
Step-by-step explanation:
to find out the probability that at least one of a pair of fair dice lands of 5, given that the sum of the dice is 8
Let A = sum of dice is 8
B = one lands in 5
P(B/A) = P(AB)/P(A) by conditional probability
P(AB) = sum is 8 and one is 5
So (5,3) or (3,5)
P(A) = sum is 8.
i.e. (2,6) (2,6) (3,5) (5,3) (4,4)
Required probability
= n(AB)/n(A)
=
Divide by 21 to put the equation in intercept form.
x/(21/9) + y/(-21/7) = 1
x/(7/3) + y/(-3) = 1
The x-intercept is (7/3, 0)
The y-intercept is (0, -3)
The 3rd choice is appropriate.
x/(21/9) + y/(-21/7) = 1
x/(7/3) + y/(-3) = 1
The x-intercept is (7/3, 0)
The y-intercept is (0, -3)
The 3rd choice is appropriate.
Doubling formula is this:
where P=initial number of rabbits
t=time
d=time it takes to doulbe
ok, so 4 weeks is the doubling time so that is 4*7=28 days
we wawnt time=98
and oroiginal number of rabbits is 5 so
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days
where P=initial number of rabbits
t=time
d=time it takes to doulbe
ok, so 4 weeks is the doubling time so that is 4*7=28 days
we wawnt time=98
and oroiginal number of rabbits is 5 so
so P(98)≈56.56
we can't have .56 rabbit so round down or up
about 56 or 57 rabbits in 98 days