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3 years ago

In the liner equation shown which variable represent the output values Y= MX + b

Mathematics

1 answer:

harkovskaia [24]3 years ago

8 0

Answer:

b=−mx+y

Step-by-step explanation:

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The cost of a babysitting on a cruise is 10 for the first hour, and 12 for each additional hour. If the total cost of baby Aaron

Sliva [168]

Answer:

5 hours was Aaron at the sitter

Explanation:

Cost of baby sitting for the first hour: 10

Cost of baby sitting for additional hour= 12

Total cost of babysitting= 58

Since the cost of first hour is 10

Hence the remaining cost after first hour

= 54-10

=48

Which means 1 hour is consumed in the first hour

Now to calculate the remaining hours for every additional hour

= $\frac{48}{12}$

=4 hours

Hence the total hour Aaron was with the sitter

= 1 hour + 4 hours

= 5 hours

4 0

3 years ago

Solve for x in the equation 2x^2+14x+17=-96

goblinko [34]

$2x^{2}+14x+17=-96 \newline
2x^{2}+14x+113=0 \newline
\Delta = b^{2}-4ac = 14^{2} - 4 \cdot 2 \cdot 113 = -708.$

Since $\Delta$ is negative $\Rightarrow x \notin \mathbb{R}.$

5 0

3 years ago

What is the answer to 846 x 21

svlad2 [7]

Your Answer 17766

Easy

5 0

3 years ago

Read 2 more answers

2350 million in standard form

topjm [15]

Answer:

in this problem we have

2,350 million

Remember that

1 million=1,000,000

2,350 million=2,350*1,000,000=2,350,000,000

convert to standard form

2,350,000,000=2.35*10^{9}

therefore

the answer is

2.35*10^{9}

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

2. Solve the equation using the quadratic formula. -4x2 + 40x + 16 = 0 Page 1 of 2

kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

Solution:

Given equation is:

$-4x^2 + 40x + 16 = 0$

To find: solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16$

Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,

$\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}$

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0

3 years ago