Consider the equation, 3x+4y=12.

A hovercraft takes off from a platform. It’s height (in meters), x seconds is modeled by h(x)=-(x-11)(x+3). What is the height o

Eddi Din [679]

Answer:

The height of the hovercraft at the time of takeoff is 33 meters.

Step-by-step explanation:

Height of hovercraft x seconds after takeoff = h(x) = -(x - 11)(x + 3)

Height after takeoff is = h(0) = -(0 - 11)(0 + 3) = -(-11)(3) = 33

So the correct answer is 33 meters. The height of the hover craft at the time of the takeoff is 33 metres.

Answer: 33 meters.

Please mark brainliest

Hope this helps

6 0

3 years ago

Helppp i dont get it

sasho [114]

Answer: Your answer will be 8 s = (8,3) but since there isn’t no 3 for your answers choice then it should be 8! Hope this help!

6 0

3 years ago

Help please!!! I dont understand these questions currently attaching photos dont delete

Katyanochek1 [597]

Answer:

b/a
16a²b²
n¹⁰/(16m⁶)
y⁸/x¹⁰
m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

$a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}$

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

$\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}$

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

$\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2$

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

$\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}$

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4. This works the same way the previous problem does.

$\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}$

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

$\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}$

3 0

3 years ago

3 to the power of -2 as a fraction

mojhsa [17]

0.03 is your answer yes

4 0

2 years ago

Which of these triangles appears not to be congruent to any others shown

Romashka [77]

Answer:

Options (B) and (D)

Step-by-step explanation:

If two triangles have the same size and shape they are said to be congruent triangles.

Triangles given in the attachment,

Triangles A and E appear to be congruent.

And triangles C and F appear to be congruent.

[Since corresponding sides of these triangles don't appear to be the same in measure]

Remaining triangles B and D do not appear to be congruent.

Therefore, Options (B) and (D) will be the answer.

7 0

3 years ago

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