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Molodets [167]
4 years ago
5

What is the answer to 6/4 fraction

Mathematics
2 answers:
Semenov [28]4 years ago
8 0

Answer:

3/2 is the most simplified

notka56 [123]4 years ago
4 0

Answer:

1.5

Step-by-step explanation:

4/4 = 1 and the left over 2/4 is equal to one half (0.5)

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There are 42 sixth-grade students and 60 fifth grade students. The students will be put in to the largest possible equal groups
scoundrel [369]

Answer:51 Groups

Step-by-step explanation:

60 students + 42 students = 102

102 divided by 2 = 51 Total groups.

5 0
4 years ago
In a school 40% are boys and 900 are girls. find the total number of students of the school and the number of boys
My name is Ann [436]

Answer:

1500 students

600 boys

Step-by-step explanation:

40% are boys, so 60% are girls.

Writing a proportion:

900 / 60% = x / 100%

x = 1500

There are 1500 students in the school, which means there are 600 boys in the school.

6 0
4 years ago
2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
11Alexandr11 [23.1K]
There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
\frac{1}{n} = \frac{1}{a} + \frac{1}{b}

\frac{1}{n} = \frac{a + b}{ab}
and thus, n = \frac{ab}{a + b}

<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = \sqrt[a]{c} = c^{\frac{1}{a}}

Then, 5 = c^{\frac{1}{b}}
and 10 = c^{\frac{1}{n}}

But, 10 = 5·2, so 10 = c^{\frac{1}{b}}·c^{\frac{1}{a}}
∴ c^{\frac{1}{n}} = c^{\frac{1}{b}}·c^{\frac{1}{a}}

\frac{1}{n} = \frac{1}{a} + \frac{1}{b}
and n = \frac{ab}{a + b}
4 0
3 years ago
What is the interquartile range of this data? A.6 B.7 C.8 D.9
Butoxors [25]
Hello!

To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile. 

33 - 25 = 8

The interquartile range is 8. Hope I helped! :3
6 0
3 years ago
1. What is the vertex of the graph of the function y=-(x + 9)^2 + 5?
dolphi86 [110]

Answer:

96

Step-by-step explanation:

96 -01

500-10 = 49

6 0
3 years ago
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