12/6 + 2/3 + 3/4
MMC of 6, 3 and 4 is 12
So 24+8+9/12 = 41/12 = 3,41 approximately.
This is the concept of quadratic equations, solving the equation 2x^2-12x+20=0 using the formula we get:
x=[-b+/-sqrt(b^2-4ac)]/(2a)
from our equation, a=2,b=-12 and c=20
x=[-(-12+/-sqrt((-12)^2-4*2*20)]/(2*2)
x=[12+/-sqrt(144-160]/4
x=[12+/-sqrt(-16)]/4
x=[12+/-4i]/4
x=[3+\-i]
the answer is A] 3+/-i
(3)(-2.5) + (-8y)(-2.5) I think lol
Answer: 1b 2c 3e? 4d 5a
<u>Step-by-step explanation:</u>
There are 2 items that need to be checked.
- The midpoint of the coordinates is the center of the circle
- The diameter of the coordinates is the diameter of the circle.
Midpoint:
Diameter:
distance between coordinates = 2√r² (from circle equation)
Check:
Graph to confirm your answers are correct (see attached)
The perimeter of a semicircle consists of two parts. (the curve and bottom)
That curve is half the distance around the circle, since it's been split in half.
The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π.
Using 3.14 for π, 8π = 8×3.14 = 25.12.
As for the flat part, that is the diameter (distance across) our circle.
The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii)
If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16.
Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
