Answer:
<h3>
x = -4</h3>
Step-by-step explanation:
vertical line is parallel to y-axis so its equation is always x = x₀
at any given point we have coordinates: (x₀, y₀)
given point (-4, 7) means x₀ = -4
so the equation of a vertical line passing through the point (-4, 7) is x=-4
Answer:
y-intercept = -4
Step-by-step explanation:
equation of a line: y=mx+b
two points given are (5, -6.5) and (-12, 2)
first we can easily find value of m or the slope, by using the slope formula. the value of m=-0.5.
formua to find m: 
= -0.5
to find the value of b (the y-intercept), we need to plug in a y and x value, we are given 2 ordered pairs, you can use either one and plug x-value in for x and the y-value in for y.
if i plug in (5, -6.5), my equation looks like this: -6.5=5(-0.5)+b
then you just solve for b and it turns out to be -4.
Answer:
I think the correct answer is 27 so option c. :)
Answer:
ok so we need to find the percent so
8.46 divided by 42.3=0.2
she she tipped 20%
Hope This Helps!!!
Step-by-step explanation:
f(x) = -0.01x² + 0.7x + 6.1
a) f(x) is a downward facing parabola, so the maximum height is at the vertex. The vertex of a parabola can be found using x = -b/(2a).
x = -0.7 / (2 × -0.01)
x = 35
f(35) = -0.01(35)² + 0.7(35) + 6.1
f(35) = 18.35
The maximum height is 18.35 feet.
b) The maximum horizontal distance is when the ball lands, or when f(x) = 0.
0 = -0.01x² + 0.7x + 6.1
0 = x² − 70x − 610
Solve with quadratic formula:
x = [ -b ± √(b² − 4ac) ] / 2a
x = [ -(-70) ± √((-70)² − 4(1)(-610)) ] / 2(1)
x = (70 ± √7340) / 2
x = 35 ± √1835
x = -7.84, 77.84
x can't be negative, so x = 77.84. The ball's maximum horizontal distance is 77.84 feet.
c) When the ball is first launched, x = 0. The height at that position is:
f(0) = 6.1
The ball is launched from an initial height of 6.1 feet.
