The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Answer:
The visual cortex in the brain processes the signals to create the perception of vision.
Explanation:
Hope this helps.
Answer:
D.) repressor DNA-binding site mutation
Explanation:
lacl prevents the repressor polypeptide is a mutant that prevent operon from binding lactose, and thus will bind to the operator and be non-inducible.. This mutant will represses the lac operon whether lactose is present or not and the lac operon will not be expressed. It is also called“super-supperesor".
The lacI locus – One type of mutant allele of lacI (callled I-) prevents the production of a repressor polypeptide or produces a polypeptide that will not allow to bind to the operator sequence.
This is also a constitutive expresser of the lac operon because absence of repressor binding permits transcription.
The allele would be called codominant
When a dominant and recessive allele exist in an organism, only the dominant allele will be expressed. Dominant allele always mask the recessive because the gene code a protein while recessive gene doesn't. When both gene code a protein, they will be codominant and both gene will be expressed. The result could be a mixed effect. In this case, the purple is mixed color of red and blue.
