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Phoenix [80]
3 years ago
15

Please help me

Mathematics
2 answers:
yarga [219]3 years ago
7 0
8-(-4)
-4-0
12/-4=-3
1/3 is the slope perpendicular to line m
Scorpion4ik [409]3 years ago
7 0

Answer:

-3

i hope this helped

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Classify the numbers as perfect squares and perfect cubes. To classify a number, drag it to the
Ratling [72]

Answer:

Pefect Squares but Not Perfect Cubes: 256, 361

Both Perfect Squares and Perfect Cubes: 1, 64

Perfect Cubes but Not Perfect Squares: 125

Step-by-step explanation:

256=16^2 ; 361=19^2

1=1^2=1^3 ; 64=8^2=4^3

125=5^3

96=6*16 (Not squares nor cubes)

200=2*100 (Not squares nor cubes)

333=37*9 (Not squares nor cubes)

7 0
4 years ago
Is the square root of 12 minus 2 irrational or rational
defon
The square root of 12 minus 2 is a rational number
7 0
3 years ago
Help Please.<br><br> Let f(x)=186+5e−0.1x . What is f(6) ?
larisa86 [58]

The answer is 186+5e-0.6

7 0
3 years ago
The vertex of a parabola is at (6,5), and its axis of symmetry is vertical. One of the x-intercepts is at (8, 0). What is the x-
Elena-2011 [213]

Answer:

x=4

Step-by-step explanation:

Vertex form of the quadratic equation: f(x) = a(x - h)^2+k

where the vertex is (h, k)

Given vertex = (6, 5):

\implies f(x) = a(x - 6)^2+5

If one the x-intercepts is (8, 0):

\implies f(8) =0

\implies a(8 - 6)^2+5=0

\implies 4a+5=0

\implies a=-\dfrac{5}{4}

Therefore, equation of parabola:

\implies f(x) = -\dfrac54(x - 6)^2+5

x-intercepts occur when f(x) = 0:

\implies f(x)=0

\implies -\dfrac54(x - 6)^2+5=0

\implies -\dfrac54(x - 6)^2=-5

\implies (x - 6)^2=4

\implies x-6=\pm 2

\implies x=8, x=4

Therefore, the x-coordinate of the other x-intercept is 4.

5 0
2 years ago
3sin²60°+3/4cot²30°-2cosec²60°-3/4tan²30°=19/12{Full process , please^^}​
Tcecarenko [31]

Answer:

3( root 3 /2)^2 + 3/4 (root 3 )^2 - 2(2/ root 3) ^2 - 3/4 (1/root3)^2

= 3 ×3 /4 + 3 × 3 /4 - 2 ×4 /3 - 3/4 × 1/3

= 9/4 + 9/4 -8/ 3 - 1/4

= 9/4 + 9/4 - 1/4 - 8/3

= 17/4 - 8/3

=( 17 × 3 - 8 × 4 )/12

= (54 -32)/12

= 19 /12

6 0
3 years ago
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