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4vir4ik [10]
2 years ago
7

Can I get some help please? ASAP Solve for X. for both equations pleaseee​

Mathematics
1 answer:
vichka [17]2 years ago
7 0

Answer:

9. \:  \boxed{ \tt{x = 7}} \\10. \: \boxed{ \tt{x = 6}}

Step-by-step explanation:

quest \: 9 \to \\  \frac{5 + x}{32}  =  \frac{9}{33 - 9}  \\ 24(5 + x) = (32)(9) \\ 5 + x =  \frac{(32)(9)}{24} \\ 5 + x = 12 \\ x = 12 - 5 \\ \boxed{ x = 7} \\  \\ quest \: 10  \to \: \\  \frac{30 - (4x - 4)}{4x - 4}  =  \frac{18 - 12}{12}  \\  \frac{34 - 4x}{4x - 4 }  =  \frac{6}{12}  =  \frac{1}{2}  \\ 2(34 - 4x) = 4x - 4 \\ 68 - 8x = 4x - 4 \\ 68 + 4 = 4x + 8x \\ 72 = 12x \\ x =  \frac{72}{12}  = 6 \\ \boxed{x = 6}

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4 0
2 years ago
Read 2 more answers
F(x) = 4x^2+5x-12 evaluate f(-3)
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4 0
3 years ago
In circle O below, what is the measure of arc ED?
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