Can I get some help please? ASAP Solve for X. for both equations pleaseee

Mathematics

1 answer:

vichka [17]3 years ago

7 0

Answer:

$9. \: \boxed{ \tt{x = 7}} \\10. \: \boxed{ \tt{x = 6}}$

Step-by-step explanation:

$quest \: 9 \to \\ \frac{5 + x}{32} = \frac{9}{33 - 9} \\ 24(5 + x) = (32)(9) \\ 5 + x = \frac{(32)(9)}{24} \\ 5 + x = 12 \\ x = 12 - 5 \\ \boxed{ x = 7} \\ \\ quest \: 10 \to \: \\ \frac{30 - (4x - 4)}{4x - 4} = \frac{18 - 12}{12} \\ \frac{34 - 4x}{4x - 4 } = \frac{6}{12} = \frac{1}{2} \\ 2(34 - 4x) = 4x - 4 \\ 68 - 8x = 4x - 4 \\ 68 + 4 = 4x + 8x \\ 72 = 12x \\ x = \frac{72}{12} = 6 \\ \boxed{x = 6}$

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Zepler [3.9K]

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Step-by-step explanation:

Let's call "x" to the number we are looking for.

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