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2 years ago

Find the product (x + 4)

Mathematics

1 answer:

vova2212 [387]2 years ago

6 0

Answer:

Step-by-step explanation:

It would be 4x because you have no value given of the variable "X"

therefore, your answer would just be adding the x to the 4 making it 4x

hope this helped!

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Simplify the following expression:<br><br> (66)4

iren [92.7K]

Step-by-step explanation:

Given

$( {6}^{6})^{4} \\ = {6}^{6 \times 4} \\ = {6}^{24} \\ = 4.7383813e18$

3 0

3 years ago

Consider a binomial experiment with n=2 and p=0.6

nalin [4]

Answer:

x=?

Step-by-step explanation:

12xn=20xp

8 0

3 years ago

Multiply the polynomials (x + 4)(x + 4)

s2008m [1.1K]

Answer:

x^2 + 8x + 16

Step-by-step explanation:

(x + 4) (x+ 4) multiply x by x and x by 4.

x^2 + 4x

Then multiply 4 by x and 4 by 4.

4x + 16

Then combine like terms.

x^2 + 4x + 4x +16

x^2 + 8x + 16

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3 years ago

help!! Katherine O’Donnell obtain a personal loan of $3000 at 14% for 24 months. The monthly payment is $144. What is the intere

lina2011 [118]

3000*0.14*24=??? Then uuu add the 144 to your answer to get your answer

8 0

3 years ago

Set up the integral that represents the arc length of the curve f(x) = ln(x) + 5 on [1, 3], and then use Simpson's Rule with n =

marta [7]

Answer:

The integral for the arc of length is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

By using Simpon’s rule we get: 1.5355453

And using technology we get: 2.3020

The approximation is about 33% smaller than the exact result.

Explanation:

The formula for the length of arc of the function f(x) in the interval [a,b] is:

$\displaystyle\int_a^b \sqrt{1+[f'(x)]^2}dx$

We need the derivative of the function:

$f'(x)=\frac{1}{x}$

And we need it squared:

$[f'(x)]^2=\frac{1}{x^2}$

Then the integral is:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx$

Now, the Simposn’s rule with n=4 is:

$\displaystyle\int_a^b g(x)}dx\approx\frac{\Delta x}{3}\left( g(a)+4g(a+\Delta x)+2g(a+2\Delta x) +4g(a+3\Delta x)+g(b) \right)$

In this problem:

$a=1,b=3,n=4, \displaystyle\Delta x=\frac{b-a}{n}=\frac{2}{4}=\frac{1}{2},g(x)= \sqrt{1+\frac{1}{x^2}}$

So, the Simposn’s rule formula becomes:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\\\approx \frac{\frac{1}{3}}{3}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{1}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(1+\frac{2}{2}\right)^2}} +4\sqrt{1+\frac{1}{\left(1+\frac{3}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then simplifying a bit:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx \approx \frac{1}{9}\left( \sqrt{1+\frac{1}{1^2}} +4\sqrt{1+\frac{1}{\left(\frac{3}{2}\right)^2}} +2\sqrt{1+\frac{1}{\left(2\right)^2}} +4\sqrt{1+\frac{1}{\left(\frac{5}{2}\right)^2}} +\sqrt{1+\frac{1}{3^2}} \right)$

Then we just do those computations and we finally get the approximation via Simposn's rule:

$\displaystyle\int_1^3\sqrt{1+\frac{1}{x^2}}dx\approx 1.5355453$

While when we do the integral by using technology we get: 2.3020.

The approximation with Simpon’s rule is close but about 33% smaller:

$\displaystyle\frac{2.3020-1.5355453}{2.3020}\cdot100\%\approx 33\%$

8 0

3 years ago

Find the product (x + 4)​

Find the product (x + 4)