Answer:
D. period costs.
Explanation:
The period cost is the cost which is incurred during the passage of time. It includes the major part of the ling and administrative expenses of the income statement. This cost is not capitalized. It is to be allocated based on the expenses that are against the revenue.  
Example - Depreciation on delivery trucks, advertising expense, etc
 
        
             
        
        
        
Answer:
Market segmentation 
Explanation:
Market segmentation is the process of dividing a market of potential customers into groups, or segments, based on different characteristics. The segments created are composed of consumers who will respond similarly to marketing strategies and who share traits such as similar interests, needs, or locations. A market segment is a group of people who share one or more common characteristics, lumped together for marketing purposes.
 
        
             
        
        
        
Specialization in production will increase output. 
As any specialization in production will be achieved by specialized labor or technology, both the factor will produce per unit time and gives a comparative advantage.
Specialization is a production method that focuses on the production of a limited range of goods for a company to achieve a higher level of efficiency.
The more they focus on their work, the more efficient they are in that work. This means less time and money is spent producing goods. In other words, you can produce more goods in the same amount of time and money.
Learn more about Specialization in production here:brainly.com/question/24448534
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Answer:
the lowest operating cost is achieved when mine 1 is operated for 0 hours and mine 2 is operated for 2 hours. 
Explanation:
Mining hours of mine 1: M1
mining hours of mine 2: M2
Objective function: Minimize operating cost < 200M1 + 160 M2
Explicit constraints:
6M1 + 2M2 ≥ 12
2M1+ 2M2≥ 8
4M1+ 12M2 ≥ 24
Implicit constraints:
M1> 0
M2>0
See the attachment for feasible region
The coordinates of feasible region are (0,0), (2,0),(0,2),(1.5,1.5)
To maximize cost substitute each of these coordinates in objective function
for(0,0)
cost=0 (neglect this cost since M1>0 and M2 >0)
for(2,0)
 cost= 320
for (0,2)
cost= 400
for (1.5,1.5)
cost= 540
the lowest operating cost is achieved when mine 1 is operated for 0 hours and mine 2 is operated for 2 hours
 
        
             
        
        
        
Who was allowed to rule Rome and establish an empire in place of the Roman public