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Answer:
0.114 kg or 114 g
Explanation:
From the diagram attaches,
Taking the moment about the fulcrum,
sum of clockwise moment = sum of anticlockwise moment.
Wd = W'd'
Where W = weight of the mass, W' = weight of the meter rule, d = distance of the mass from the fulcrum, d' = distance of the meter rule.
make W' the subject of the equation
W' = Wd/d'................ Equation 1
Given: W = mg = 0.0515(9.8) = 0.5047 N, d = (39.2-16) = 23.2 cm, d' = (49.7-39.2) = 10.5 cm
Substitute these values into equation 1
W' = 0.5047(23.2)/10.5
W' = 1.115 N.
But,
m' = W'/g
m' = 1.115/9.8
m' = 0.114 kg
m' = 114 g
Answer:
$1,105.69
Explanation:
For this question we use the Present value formula that is shown on the attachment. Kindly find it below:
Given that,
Future value = $1,000
Rate of interest = 8.4% ÷ 2 = 4.2%
NPER = 20 years × 2 = 40 years
PMT = $1,000 × 9.5% ÷ 2 = $47.50
The formula is shown below:
= -PV(Rate;NPER;PMT;FV;type)
So, after solving this, the maximum price pay for the bond is $1,105.69
