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kenny6666 [7]
2 years ago
6

The radius of a circle is 16 cm. Find its area in terms of \piπ

Mathematics
1 answer:
Kitty [74]2 years ago
3 0

Answer256pi

Step-by-step explanation:

Area=pi*r^2

=pi*16^2

256pi

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The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance betw
Romashka-Z-Leto [24]

Diameter of the basketball rim = 18 inches

Circumference of the standard basketball = 30 inches

Area of circle = π r²  

Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²

Circumference of a circle = 2 π r

30 = 2 * 3.14 * r

r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches

Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²

254.34 - 71.75 = 182.59 in²

7 0
3 years ago
Read 2 more answers
How are slope 1 and slope 2 related?
Diano4ka-milaya [45]
The answer is B. Adjacent angles. They both have a meeting point and don't overlap.
The answer isn't A. because both angles don't add up to 90°.
The answer isn't C. because both angles aren't 90°.
The answer isn't D. because both angles don't add up to 180°.

Hope this helps! :)

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6 0
3 years ago
Renna pushed the button for the elevator to go up, but it would not move. The weight limit for the elevator is 450 kilograms, bu
alina1380 [7]
Here is the solution based on the given situation above.
Given: 450 kg = weight limit of the elevator
           750 kg = current weight of the group of passengers
           ? = number of passengers who weigh 70 kgs that need to get off the elevator
So to get the answer, first we need to deduct 450kg from 750 kgs to get the excess weight. So 750 - 450 is 300kgs. Next, we divide 300 by 70kgs to get the number of passengers that need to get off so 300/70 is 4.3. Therefore, there should be 4 passengers who weigh 70 kilograms that need to get off the elevator. 
3 0
3 years ago
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Suppose the function y = 30,000(1.06)x models the annual profit for a small business x years after 2000. Find the profit at the
goldfiish [28.3K]
From 2000 to 2011, there are 11 years. From the given function, we can calculate the profit for a small business at the end of 2011 by substituting 11 to the x of the given equation. 
                                         y = (30,000)(1.06)(11)
                                         y = 349,800
Thus, the profit at the end of 2011 is approximately $349,800. 
4 0
3 years ago
Haruka owns an umbrella factory. The revenue, RRR, she makes from selling nnn umbrellas is given by the function R(n)=18nR(n)=18
Levart [38]

<u>Answer:</u>

E(n) = n + 5


<u>Explanation:</u>

The profit is the difference between the amount of money received as a revenue and the amount of money spent as expenses.

<u>This means that:</u>

Profit = Revenue - Expenses


<u>Rearrange the formula to solve for the expenses, we get:</u>

Expenses = Revenue - Profit


<u>We are given that: </u>

Revenue = R(n) = 18n

Profit = P(n) = 17n - 5


<u>Substitute in the above formula to get the formula for expenses as follows:</u>

E(n) = R(n) - P(n)

E(n) = 18n - (17n-5)

E(n) = 18n - 17n + 5

E(n) = n + 5


Hope this helps :)

5 0
3 years ago
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