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Cloud [144]
3 years ago
14

Determine graphically the​ x-value when y

Mathematics
1 answer:
Mademuasel [1]3 years ago
8 0
This problem is very simple. Knowing that y=2, plug 2 into the "y" in the equation: -x+2(2)=8

-x+4=8 
subtract 4 on both sides of the equation:
-x=(8-4)
-x=4
Divide both sides of the equation by (-1):
x=(-4)
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-5 less than or equal to 2 (x+4) less than 8
aalyn [17]
This is what I got for the inequality

4 0
3 years ago
Is 3.65 greater than, less than, or equal to 3 3/4?​
lawyer [7]

3.65 is less than 3\frac{3}{4}

First, you must change the mixed number into a decimal so you can compare the two numbers.

3\frac{3}{4} = 3.75

Then, you must compare the terms.

3.65 < 3.75

3.65 is less than 3\frac{3}{4}

7 0
4 years ago
Please help me I am so confused it would mean a lot.
Alisiya [41]

Step-by-step explanation:

1. The midpoint formula says the coordinates of the midpoint are the average of the endpoints.

x = (x₁ + x₂) / 2

y = (y₁ + y₂) / 2

I'll do #2 and #3 as examples.

2. x = (-4 + 10) / 2 = 3

y = (6 + -10) / 2 = -2

So the midpoint is (3, -2).

3. x = (-3 + -6.5) / 2 = -4.75

y = (-8 + -4.5) / 2 = -6.25

So the midpoint is (-4.75, -6.25).

5 0
3 years ago
A cup of coffee contains 130 mg of caffeine. If caffeine is eliminated from the body at a rate of 11% per hour, how much caffein
german
---<span>
y(t) = a*e^(kt)</span><span>
---
now:</span><span>
130 mg</span><span>
---
one hour from intake:</span><span>
130 * (1 - 0.11) = 115.7 mg</span><span>
---
y(1) = 115.7 = 130*e^(k(1))</span><span>
115.7 = 130*e^k</span><span>
115.7/130 = e^k</span><span>
ln( 115.7/130 ) = ln( e^k )</span><span>
ln( 115.7/130 ) = k</span><span>
k = -0.1165338

</span><span>---
three hours from intake:</span><span>
y(3) = 130*e^(3k)</span><span>
y(3) = 91.64597</span><span>
---
answer:</span><span>
three hours after drinking a cup of coffee, 91.6 mg of caffeine will remain in the body

</span>
7 0
4 years ago
For $x$, $y$, and $z$ positive real numbers, what is the maximum possible value for\[\sqrt{\frac{3x 4y}{6x 5y 4z}} \sqrt{\frac{y
joja [24]

Answer:

Infinity

Step-by-step explanation:

Since x,y,z are positive rel numbers, we have that

\dfrac{3x4y}{6x5y4z}=\dfrac{1}{10z}\\\\\\\dfrac{y2z}{6x5y4z}=\dfrac{1}{60x}\\\\\\\dfrac{2z3x}{6x5y4z}=\dfrac{1}{20y}

Hence,

\sqrt{\dfrac{3x4y}{6x5y4z}}\sqrt{\dfrac{y2z}{6x5y4z}}\sqrt{\dfrac{2z3x}{6x5y4z}}\\\\\\=\sqrt{\dfrac{1}{10z}\dfrac{1}{60x}\dfrac{1}{20y}}=\sqrt{\dfrac{1}{12000xyz}}

Now let

f(x,y,z)=\sqrt{\dfrac{1}{12000 xyz}}

if we take x=y=1, we have

f(1,1,z)=\sqrt{\dfrac{1}{12000z}}

and so f(1,1,z) tends to infinity as z goes to 0.

7 0
4 years ago
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