All categories

3 years ago

0 = a + 27.98 Please I need help

Mathematics

2 answers:

fiasKO [112]3 years ago

4 0

Answer:

a=-27.98

Step-by-step explanation:

cancel out the 27.98 with the negative and you get 0

pogonyaev3 years ago

3 0

Answer:

a = -27.98

Step-by-step explanation:

You might be interested in

In the expansion of (3a + 4b)8, which of the following are possible variable terms? Explain your reasoning. a2b3; a5b3; ab8; b8;

Fiesta28 [93]

We have to find the expansion of $(3a+4b)^{8}$

We will use binomial expansion to expand the given expression, which states that the expression $(a+b)^{n}$ is expanded as :

$(a+b)^{n}=^{n}C_{0}a^{n}+^{n}C_{1}a^{n-1}b+^{n}C_{2}a^{n-2}b^{2}+........^{n}C_{n}b^{n}$

Now expanding $(3a+4b)^{8}$ we get,

$(3a+4b)^{8}=^{8}C_{0}(3a)^{8}+^{8}C_{1}(3a)^{7}(4b)+^{8}C_{2}(3a)^{6}(4b)^{2}+^{8}C_{3}(3a)^{5}(4b)^{3}+^{8}C_{4}(3a)^{4}(4b)^{4}+^{8}C_{5}(3a)^{3}(4b)^{5}+^{8}C_{6}(3a)^{2}(4b)^{6}+^{8}C_{7}(3a)(4b)^{7}+^{8}C_{8}(4b)^{8}$

$(3a+4b)^{8}=^{8}C_{0}(3)^{8}a^{8}+^{8}C_{1}(3)^{7}(4)(a^{7}b)+^{8}C_{2}(3)^{6}(4)^{2}(a^{6}b^{2})+^{8}C_{3}(3)^{5}(4)^{3}(a^{5}b^{3})+^{8}C_{4}(3)^{4}(4)^{4}(a^{4}b^{4})+^{8}C_{5}(3)^{3}(4)^{5}(a^{3}b^{5})+^{8}C_{6}(3)^{2}(4)^{6}(a^{2}b^{6})+^{8}C_{7}(3)(4)^{7}(ab^{7})+^{8}C_{8}(4)^{8}(b^{8})$

So, the variables are $a^{5}b^{3}$ , $b^{8}$ , $a^{4}b^{4}$ , $a^{8} , [tex] ab^{7}$

5 0

3 years ago

Help in giving brainlist

Lina20 [59]

Answer:

50%

Step-by-step explanation:

25 x 50% = 12.5

12.5$ off is more than 10$ off

7 0

3 years ago

Read 2 more answers

A man is running a race. He starts a 0 and makes it to the 350 feet marker. It took him 7 minutes. How many feet can the man run

mel-nik [20]

350 divided by 7 is 50 so the man can run 50 feet in one minute

6 0

4 years ago

Based on a poll, 60% of adults believe in reincarnation. Assume that 5 adults are randomly selected, and find the indicated p

vlabodo [156]

Answer:

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they believe in reincarnation, or they do not believe. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 5 adults, so $n = 5$

60% believe in reincarnation, so $p = 0.6$

What is the probability that exactly 4 of the selected adults believe in reincarnation?

This is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

There is a 25.92% probability that exactly 4 of the selected adults believe in reincarnation.

3 0

3 years ago

What are the bounds of integration?

Elodia [21]

I really hope this is right ! Pleas forgive me if it isn’t . A mathematical analysis of integration of intergal . So basically the region that is bounded . (Example [DX]

7 0

3 years ago

Read 2 more answers