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3 years ago

Help with proofs (10 points) please help will give brainliest

Mathematics

1 answer:

stiks02 [169]3 years ago

3 0

1: e
2: d
3: g
4: c
5: a
6: i
7: h
8: f
i believe this is correct

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Which of the following phrases are equations? Choose 2 answers:

Ksivusya [100]

Answer:

the answers are Band C

Step-by-step explanation:

B. using the number line n greater than -8

C.8=4.2

8=8

4 0

3 years ago

A dolphin is at -- 28 feet. It swims up and jumps out of the water to a height of 8 feet. Find the vertical distance the dolphin

Helga [31]

Answer:

The vertical depth travelled by the dolphin = 36 feet

Step-by-step explanation:

The dolphin is a fish that can jump out of the water and therefore it is used in circus shows and exhibitions.

Initially the dolphin is at a depth of 28 feet deep inside the water surface.It comes to water surface and then jumps out of the water to a height of 8 feet.

The vertical distance travelled by the dolphin can be found by taking the difference of final height and initial depth.

Vertical depth = final height - initial depth

= 8 - (-28)

= 36 feet

The vertical depth travelled by the dolphin = 36 feet

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4 years ago

Given triangle TVU list the sides of the shortest to longest

Margaret [11]

Answer:

VU, VT, TU

Step-by-step explanation:

List the side lengths of triangle TUV from shortest to longest.

A. VU, VT, TU

B. VT, TU, VU

C. VT, VU, TU

D. VU, TU, VT"

8 0

3 years ago

Let f ( x , y )=5 x and let C be the segment of the parabola y = 2 x squared joining O( 0 , 0 ) and P( 1 , 2 ). a. Find a parame

taurus [48]

a. We can parameterize $C$ by

$x=t$

$y=2t^2$

with $0\le t\le1$ . Then

$\displaystyle\int_C5x\,\mathrm dS=\int_0^15t\sqrt{1+16t^2}\,\mathrm dt=\dfrac5{48}(17^{3/2}-1)$

b. We can parameterize the opposite direction by instead setting

$x=1-t$

$y=2(1-t)^2$

with $0\le t\le 1$ . Then

$\displaystyle\int_C5x\,\mathrm dS=\int_0^15(1-t)\sqrt{1+16(1-t)^2}\,\mathrm dt=-\int_1^05u\sqrt{1+16u^2}\,\mathrm dt=\int_0^15u\sqrt{1+16u^2}\,\mathrm du$

which gives the same value as in part (a).

5 0

4 years ago

During a two-hour period, the temperature in a city dropped from a high of 51°F to a low of −11°F. What was the range of the tem

Likurg_2 [28]

you have to take 51 plus 11 and add it up. then your answer should be 62 degrees different.

6 0

3 years ago