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TiliK225 [7]
3 years ago
15

Lines are drawn through the point (2, 8) and the points given below. Select two points that correspond with lines with negative

slopes.
(-2, -6)
(0, 9) (
1, -3)
(5, 6)
(10, 11)
Mathematics
1 answer:
aleksley [76]3 years ago
5 0
Since the slope is (change in y)/(change in x), and a negative number over a positive number is negative (and vice versa), we want to figure that out. Therefore, we would want 2 to be bigger than the x value and 8 smaller than the y value, or the other way around. (0,9) fits the description, as well as (5, 6)
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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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5 0
3 years ago
The vertices of a triangle are P(-2, -4), Q(2, -5), and R(-1,-8). Name the vértices of the triangle after reflecting over the x-
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7 0
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larisa86 [58]

Step-by-step explanation:

Do you mean?

\frac{ { \tan(x) }^{2} }{ \ { \sin(x) }^{2}  }

If so:

3 \sin(x)  = 4 \cos(x)  \\  \frac{3 \sin(x) }{ \cos(x) }  = 4 \\   \frac{ \sin(x) }{ \cos(x) }   =  \frac{4}{3}  \\  \tan(x)  =  \frac{4}{3}

Did the question specify which quadrant? I'm just going to assume that it's the first

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hence

Hypotenuse:

\sqrt{{3}^{2} +  {4}^{2}  }  = 5

\sin(x)  =  \frac{4}{5}

Finally,

\frac{ { \tan(x) }^{2} }{ { \sin(x) }^{2} }  =  \frac{ { \frac{4}{3} }^{2} }{ { \frac{4}{5} }^{2} }  \\  = 2  \frac{7}{9}

8 0
4 years ago
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