Question

Renee has dimes and quarters in her wallet that total $1.60. She has 2 more dimes than quarters.

Answer 1

Given:

Renee has dimes and quarters in her wallet that total $1.60.

She has 2 more dimes than quarters.

To find:

The number of each type of coins.

Solution:

Let x be the number of dimes and y be the number of quarters.

She has 2 more dimes than quarters. So,

$x=y+2$            ...(i)

We know that,

1 dime = $0.10

1 quarter = $0.25

Renee has dimes and quarters in her wallet that total $1.60. So,

$0.10x+0.25y=1.60$              ...(ii)

From (i) and (ii), we get

$0.10(y+2)+0.25y=1.60$

$0.10y+0.20+0.25y=1.60$

$0.35y=1.60-0.20$

$0.35y=1.40$

Divide both sides by 0.35.

$y=\dfrac{1.40}{0.35}$

$y=4$

Substituting $y=4$ in (i), we get

$x=4+2$

$x=6$

Therefore, the number of dimes is 6 and the number of quarters is 4.