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allochka39001 [22]
3 years ago
7

Find the product of

0%20%5Ctimes%20%20%5Csqrt%5B12%5D%7B32%7D%20" id="TexFormula1" title=" \sqrt[3]{2 } \times \sqrt[4]{2} \times \sqrt[12]{32} " alt=" \sqrt[3]{2 } \times \sqrt[4]{2} \times \sqrt[12]{32} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Grace [21]3 years ago
6 0
The product is 2. Hope this helps
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Describe how you would find the area of the figure shown at the right.
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I would find the area of the shape as if it were a rectangle (5x9) and then subtract the area of two triangles (1/2x2x2.5)
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#2 Find the value of x. Round to the nearest degree.
Sergio [31]

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49°

Step-by-step explanation:

arccos x = 15/23

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ABCDE ~ FGHIJ. Figure 2 is a dilation of figure 1, and the scale factor is 0.6. Given that FG = 12 cm, find AB.
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We known that the figures are similar if and only if the corresponding sides and and angles have the common scale factor. In this item, the scale factor is 0.6. The length of AB is determined by multiplying the length of FG with the scale factor. That is,
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We can use the formula, density = mass over volume, to find the density of a substance. A square metal plate has a density of 10
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A car of 1000 kg starts to move from rest and travels a distance of 150 m in 10 second. How much force is needed?​
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Using second equation of kinematics

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2

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