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sineoko [7]
3 years ago
12

Solve the absolute value inequality |4x+7|-2|-x-2|≥2x+3

Mathematics
1 answer:
yarga [219]3 years ago
5 0
X= any real number :))
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Check all that apply. pi/4 is the reference angle for:
ANEK [815]

Answer:

answer is c

I took a quiz with the question and got 100%

3 0
2 years ago
8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components
Taya2010 [7]

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of <u>exactly x successes on n repeated trials, with p probability</u>, and has variance given by:

V(X) = np(1 - p)

In this problem:

  • 95% pass final inspection, hence p = 0.95
  • 120 components are inspected in one day, hence n = 120.

The variance is given by:

V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at brainly.com/question/24863377

3 0
2 years ago
The answer that go in the box? Please help
saul85 [17]
Transaction 3 - $143
transaction 4 - $-86
transaction 5 - $86
3 0
2 years ago
PLS HELP!!!!!
Crank

Answer:If you would like to know what will the approximate population be after 3 years, you can calculate this using the following steps:

an initial population ... 298 quail

an annual rate ... 8%

an exponential function to model the quail population:

f = 298(1+8%)^t = 298(1+8/100)^t

f ... quail population

t ... time (years)

t = 3 years

f = 298(1+8/100)^t = 298(1.08)^3 = 375.4 quail

375.4 quail after 3 years.

5 0
3 years ago
Read 2 more answers
To qualify for a police academy, candidates must score in the top 10% on a general abilities test. The test has a mean of 200 an
kolbaska11 [484]

Answer:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

Step-by-step explanation:

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X ~ N (200,20)

For u = 200 and o = 20

For this case we can use the z score in order to solve this problem, given by this formula:

Z = x-u/o

For this part we want to find a value a, such that we satisfy this condition:

P (X > a) = 0.1 (a)

P (X < a) = 0.9 (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.9 of the area on the left and 0.1 of the area on the right it's z=1.28. On this case P(Z<1.28)=0.9 and P(z>1.28)=0.1

If we use condition (b) from previous we have this:

P ( X < a) = P (X-u/o < a - u/o) = 0.9

P (z < a-u/o) = 0.9

But we know which value of z satisfy the previous equation so then we can do this:

z = 1.28 < a - 200/20

And if we solve for a we got

a = 200 + 1.28 * 20 = 225.6

So the value of height that separates the bottom 90% of data from the top 10% is 225.6.  

3 0
2 years ago
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