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Nitella [24]
3 years ago
7

Which of the following equations have no solutions?

Mathematics
2 answers:
DiKsa [7]3 years ago
6 0

A and C

Step-by-step explanation:

Im sorry I've got homework too

Alex73 [517]3 years ago
5 0

Answer:

C

Step-by-step explanation

A. -4x+5 =-4 -4

-4x+5-5=-8-5

-4x=-13

x=3.25

B.-4x+5=-43-5

-4x+5=-48

-4x-5+5=-48-5

-4x=-53

x=13.24

C.4x+5=-4x+5

The 5's would cancel out leaving -4x≠4x

D. 5x+5= -4-5

5x-5+5=-9-5

5x=-14

x=-2.8

As long these -x-x=-y and stuff. I hope this helps!

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Which inequality has a solution that is the set of all real numbers?
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Answer:

12<14

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Step-by-step explanation:

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6 0
3 years ago
Find the domain of the function y = 3 tan(23x)
solmaris [256]

Answer:

\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

In other words, the x in f(x) = 3\, \tan(23\, x) could be any real number as long as x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) for all integer k (including negative integers.)

Step-by-step explanation:

The tangent function y = \tan(x) has a real value for real inputs x as long as the input x \ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

Hence, the domain of the original tangent function is \mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

On the other hand, in the function f(x) = 3\, \tan(23\, x), the input to the tangent function is replaced with (23\, x).

The transformed tangent function \tan(23\, x) would have a real value as long as its input (23\, x) ensures that 23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2} for all integer k.

In other words, \tan(23\, x) would have a real value as long as x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right).

Accordingly, the domain of f(x) = 3\, \tan(23\, x) would be \mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)  \; \right| k \in \mathbb{Z}  \right\rbrace.

4 0
3 years ago
Work out the percentage to change to decimal places when a price of 200 is increased to 210.99
olya-2409 [2.1K]

Answer:

105.495%

Step-by-step explanation:

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200 * 1.05495 = 210.99

6 0
3 years ago
Help plz...
tino4ka555 [31]

Answer:

A

Step-by-step explanation:

4^3+7=4^10

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